cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A135893 Triangle, read by rows, equal to P^6, where triangle P = A135880; also equals Q^3 where Q = P^2 = A135885.

Original entry on oeis.org

1, 6, 1, 42, 12, 1, 351, 132, 18, 1, 3470, 1554, 270, 24, 1, 39968, 20260, 4089, 456, 30, 1, 528306, 294218, 65874, 8436, 690, 36, 1, 7906598, 4745522, 1147662, 161576, 15075, 972, 42, 1, 132426050, 84534154, 21710680, 3277148, 334390, 24486, 1302
Offset: 0

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Author

Paul D. Hanna, Dec 15 2007

Keywords

Comments

Triangle P = A135880 is defined by: column k of P^2 equals column 0 of P^(2k+2) such that column 0 of P^2 equals column 0 of P shift left.

Examples

			Triangle P^6 = Q^3 begins:
1;
6, 1;
42, 12, 1;
351, 132, 18, 1;
3470, 1554, 270, 24, 1;
39968, 20260, 4089, 456, 30, 1;
528306, 294218, 65874, 8436, 690, 36, 1;
7906598, 4745522, 1147662, 161576, 15075, 972, 42, 1;
132426050, 84534154, 21710680, 3277148, 334390, 24486, 1302, 48, 1;
2457643895, 1652665714, 445574768, 70977244, 7732100, 617100, 37149, 1680, 54, 1;
where P = A135880 begins:
1;
1, 1;
2, 2, 1;
6, 7, 3, 1;
25, 34, 15, 4, 1;
138, 215, 99, 26, 5, 1;
970, 1698, 814, 216, 40, 6, 1; ...
and Q = P^2 = A135885 begins:
1;
2, 1;
6, 4, 1;
25, 20, 6, 1;
138, 126, 42, 8, 1;
970, 980, 351, 72, 10, 1;
8390, 9186, 3470, 748, 110, 12, 1; ...
where column k of Q = column 0 of Q^(k+1).
		

Crossrefs

Cf. A135887 (column 0); A135880 (P), A135885 (Q=P^2), A135891 (Q^2).

Programs

  • PARI
    {T(n,k)=local(P=Mat(1),R,PShR);if(n>0,for(i=0,n, PShR=matrix(#P,#P, r,c, if(r>=c,if(r==c,1,if(c==1,0,P[r-1,c-1]))));R=P*PShR; R=matrix(#P+1, #P+1, r,c, if(r>=c, if(r<#P+1,R[r,c], if(c==1,(P^2)[ #P,1],(P^(2*c-1))[r-c+1,1])))); P=matrix(#R, #R, r,c, if(r>=c, if(r<#R,P[r,c], (R^c)[r-c+1,1])))));(P^6)[n+1,k+1]}

Formula

Column k of Q^3 = column 2 of Q^(k+1) for k>=0 where triangle Q = P^2 = A135885; column 0 of Q^3 = column 2 of Q; column 1 of Q^3 = column 2 of Q^2.