cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 10 results.

A138493 Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 9.

Original entry on oeis.org

9, 19, 1911, 3119, 192113, 13311219, 19411223, 1322311419, 1941142322, 3213243119, 1931331422, 2214313319, 1931331422, 2214313319, 1931331422, 2214313319, 1931331422, 2214313319, 1931331422, 2214313319, 1931331422
Offset: 0

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Keywords

Comments

After a while sequence has period 2 -> {1931331422,2214313319}

Examples

			To get the term after 192113, we say: one 3's, three 1's, one 2's, one 9's, so 13311219
		

Crossrefs

A138485 Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 1.

Original entry on oeis.org

1, 11, 21, 1112, 1231, 211312, 223113, 232122, 421113, 13311214, 14411223, 13223124, 14322123, 23322114, 14213223, 23322114, 14213223, 23322114, 14213223, 23322114, 14213223, 23322114, 14213223, 23322114, 14213223
Offset: 0

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Keywords

Comments

After a while sequence has period 2 -> {23322114,14213223}

Examples

			To get the term after 211312, we say: two 2's, three 1's, one 3's, so 223113.
		

Crossrefs

A138486 Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 2.

Original entry on oeis.org

2, 12, 1211, 3112, 122113, 133122, 222123, 134211, 31121413, 23411412, 22312413, 23211432, 32231421, 21321423, 23321421, 21321423, 23321421, 21321423, 23321421, 21321423, 23321421, 21321423, 23321421, 21321423
Offset: 0

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Comments

After a while sequence has period 2 -> {21321423,23321421}

Examples

			To get the term after 122113, we say: one 3's, three 1's, two 2's, so 133122
		

Crossrefs

Extensions

Duplicate term 21321423 removed by Georg Fischer, Sep 18 2023

A138487 Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 3.

Original entry on oeis.org

3, 13, 1311, 3113, 2321, 112213, 133122, 222123, 134211, 31121413, 23411412, 22312413, 23211432, 32231421, 21321423, 23321421, 21321423, 23321421, 21321423, 23321421, 21321423, 23321421, 21321423, 23321421, 21321423
Offset: 0

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Keywords

Comments

After a while sequence has period 2 -> {21321423,23321421}

Examples

			To get the term after 112213, we say: one 3's, three 1's, two 2's, so 133122
		

Crossrefs

A138488 Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 4.

Original entry on oeis.org

4, 14, 1411, 3114, 142113, 13311214, 14411223, 13223124, 14322123, 23322114, 14213223, 23322114
Offset: 0

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Comments

After a while sequence has period 2 -> {23322114,14213223}

Examples

			To get the term after 142113, we say: one 3's, three 1's, one 2's, one 4's, so 13311214
		

Crossrefs

A138489 Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 5.

Original entry on oeis.org

5, 15, 1511, 3115, 152113, 13311215, 15411223, 1322311415, 1541142322, 3213243115, 1531331422, 2214313315, 1531331422, 2214313315, 1531331422, 2214313315, 1531331422, 2214313315, 1531331422, 2214313315, 1531331422
Offset: 0

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Comments

After a while sequence has period 2 -> {1531331422,2214313315}

Examples

			To get the term after 152113, we say: one 3's, three 1's, one 2's, one 5's, so 13311215
		

Crossrefs

A138490 Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 6.

Original entry on oeis.org

6, 16, 1611, 3116, 162113, 13311216, 16411223, 1322311416, 1641142322, 3213243116, 1631331422, 2214313316, 1631331422, 2214313316, 1631331422, 2214313316, 1631331422, 2214313316, 1631331422, 2214313316, 1631331422
Offset: 0

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Comments

After a while sequence has period 2 -> {1631331422,2214313316}

Examples

			To get the term after 162113, we say: one 3's, three 1's, one 2's, one 6's, so 13311216
		

Crossrefs

A138491 Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 7.

Original entry on oeis.org

7, 17, 1711, 3117, 172113, 13311217, 17411223, 1322311417, 1741142322, 3213243117, 1731331422, 2214313317, 1731331422, 2214313317, 1731331422, 2214313317, 1731331422, 2214313317, 1731331422, 2214313317, 1731331422
Offset: 0

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Comments

After a while sequence has period 2 -> {1731331422,2214313317}

Examples

			To get the term after 172113, we say: one 3's, three 1's, one 2's, one 7's, so 13311217
		

Crossrefs

A138492 Say what you see in previous term, from the right, reporting total number for each digit encountered. Initial term is 8.

Original entry on oeis.org

8, 18, 1811, 3118, 182113, 13311218, 18411223, 1322311418, 1841142322, 3213243118, 1831331422, 2214313318, 1831331422, 2214313318, 1831331422, 2214313318, 1831331422, 2214313318, 1831331422, 2214313318, 1831331422
Offset: 0

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Comments

After a while sequence has period 2 -> {1831331422,2214313318}

Examples

			To get the term after 182113, we say: one 3's, three 1's, one 2's, one 8's, so 13311218
		

Crossrefs

A194854 Starting from a(1)=1, describe previous terms and then add all the digits.

Original entry on oeis.org

1, 2, 5, 11, 13, 18, 28, 30, 32, 34, 40, 42, 44, 46, 54, 56, 58, 60, 62, 64, 66, 68, 70, 79, 90, 92, 94, 96, 98, 100, 103, 106, 100, 94, 87, 89, 91, 84, 86, 88, 81, 83, 85, 87, 89, 82, 84, 86, 88, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99, 101, 104, 107, 110, 113
Offset: 1

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Author

Paolo P. Lava, Sep 07 2011

Keywords

Examples

			Start with 1. There is one 1: 11 and 1+1=2. The sequence is now 1,2. Therefore one 1 and one 2: 1112 and 1+1+1+2=5. The sequence is now 1,2,5. Again: 111215 and 1+1+1+2+1+5=11. And so on.
		

Crossrefs

Programs

  • Maple
    sd:=proc(j)
    local c,d,h,k;
    h:=j; c:=0;
    if h>0 then
       d:=floor(evalf(log10(h))+1);
       for k from 1 to d do c:=c+h-10*trunc(h/10); h:=trunc(h/10); od;
    fi;
    c;
    end:
    P:=proc(i)
    local a,b,f,n,p,s,v;
    v:=array[10]; v[1]:=1; v[10]:=0; print(v[1]);
    for n from 2 to 9 do v[n]:=0; od;
    for n from 1 by 1 to i do
       a:=0;
       for p from 1 to 10 do
         if sd(v[p])=0 then a:=a+sd(v[p]);
         else a:=a+(p mod 10)+sd(v[p]);
         fi;
       od;
       print(a); s:=floor(evalf(log10(a))+1);
       for p from 1 to s do
         f:=a-10*trunc(a/10); a:=trunc(a/10);
         if f=0 then v[10]:=v[10]+1; else v[f]:=v[f]+1; fi;
       od;
    od;
    end:
    P(10000);
Showing 1-10 of 10 results.