A141323 Number of groups of order L(n).

1, 1, 1, 2, 1, 1, 5, 1, 1, 4, 1, 1, 4, 2, 1, 9, 1, 1, 30, 1, 1, 11, 5, 1, 4, 1, 2, 9, 2, 1

Offset: 0

Author

Jonathan Vos Post, Aug 02 2008

Keywords

• more
• nonn

Comments

This is to A140987 as Lucas numbers A000032 are to Fibonacci numbers A000045.

Examples

			a(6) = 5 because the Lucas number L(6) (starting at L(0) = 2) is 18 and there are 5 groups of order 18.
		

Links

• GAP package GrpConst

Crossrefs

Cf. A000001, A000032, A000045, A140987.

Formula

a(n) = A000001(A000032(n)).

Extensions

a(16)-a(29) from Eric M. Schmidt, Jun 20 2014