A144016 a(n) = the largest positive integer m such that the binary representations of all positive integers <= m are found within the binary representation of n.
1, 2, 1, 2, 2, 3, 1, 2, 2, 2, 3, 4, 3, 3, 1, 2, 2, 2, 4, 2, 2, 3, 3, 4, 4, 3, 3, 4, 3, 3, 1, 2, 2, 2, 4, 2, 2, 4, 4, 2, 2, 2, 3, 6, 3, 3, 3, 4, 4, 4, 4, 6, 3, 3, 3, 4, 4, 3, 3, 4, 3, 3, 1, 2, 2, 2, 4, 2, 2, 4, 4, 2, 2, 2, 5, 4, 6, 4, 4, 2, 2, 2, 5, 2, 2, 3, 3, 6, 6, 3, 3, 7, 3, 3, 3, 4, 4, 4, 4, 4, 6, 4, 4, 6, 6
Offset: 1
Examples
44 in binary is 101100. In this string we find 1 (1 in decimal): (1)01100; 10 (2 in decimal): (10)1100; 11 (3 in decimal): 10(11)00; 100 (4 in decimal): 101(100); 101 (5 in decimal): (101)100; and 110 (6 in decimal): 10(110)0; but not 111 (7 in decimal). So a(44) = 6.
Links
- Rémy Sigrist, Table of n, a(n) for n = 1..10000
Formula
a(n) = A261461(n) - 1. - Rémy Sigrist, Mar 10 2018
Extensions
Extended by Ray Chandler, Nov 07 2008
Comments