A144066 T(n, k) is the number of order-preserving partial transformations (of an n-element chain) of height k (height(alpha) = |Im(alpha)|); triangle T read by rows.
1, 1, 1, 1, 6, 1, 1, 21, 15, 1, 1, 60, 102, 28, 1, 1, 155, 490, 310, 45, 1, 1, 378, 1935, 2220, 735, 66, 1, 1, 889, 6741, 12285, 7315, 1491, 91, 1
Offset: 0
Examples
Triangle T(n,k) (with rows n >= 0 and columns k = 0..n) begins: 1; 1, 1; 1, 6, 1; 1, 21, 15, 1; 1, 60, 102, 28, 1; 1, 155, 490, 310, 45, 1; 1, 378, 1935, 2220, 735, 66, 1; 1, 889, 6741, 12285, 7315, 1491, 91, 1; ... T(2,1) = 6 because there are exactly 6 order-preserving partial transformations (on a 2-element chain) of height 1, namely: (1)->(1), (1)->(2), (2)->(1), (2)->(2), (1,2)->(1,1), and (1,2)->(2,2) -- the mappings are coordinate-wise.
Links
- A. Laradji and A. Umar, Combinatorial results for semigroups of order-preserving partial transformations, Journal of Algebra, 278 (2004), 342-359.
- A. Laradji and A. Umar, Combinatorial results for semigroups of order-decreasing partial transformations, J. Integer Seq., 7 (2004), 04.3.8.
Formula
T(n,k) = C(n,k)*A112857(n,k) for 0 <= k <= n.
C(n-1,k-1)*T(n,k) = 2((n-k+1)/(n-k))*T(n-1,k) + C(n,k)*T(n-1,k-1). [This is wrong.]
From Petros Hadjicostas, Feb 14 2021: (Start)
T(n,k) = 2*n*T(n-1,k)/(n-k) + n*T(n-1,k-1)/k for 1 <= k <= n-1 with T(n,0) = T(n,n) = 1 for n >= 0.
T(n,1) = n*(2^n - 1) = A066524(n) for n >= 1.
T(n,n-1) = n*(2*n - 1) = A000384(n) for n >= 1.
T(n,n-2) = A076454(n-1) for n >= 2. (End)
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