A144182 -id:A144182 - cp's OEIS frontend

A144181 INVERT transform of A118434, = row sums of triangle A144182.

1, 1, 3, 9, 11, 17, 35, 57, 91, 161, 275, 457, 779, 1329, 2243, 3801, 6459, 10945, 18547, 31465, 53355, 90449, 153379, 260089, 440987, 747745, 1267923, 2149897, 3645387, 6181233, 10481027, 17771801, 30134267, 51096321, 86639923, 146908457, 249101099

Offset: 0

Gary W. Adamson, Sep 13 2008

A118434 = row sums of the self-inverse triangle A118433 (a generator for the Rao Uppuluri-Carpenter numbers, A000587).

A144181 = row sums of triangle A144182.

			a(3) = 9 = sum of row 3 terms, triangle A144182: (4 + 2 + 0 + 3).

Colin Barker, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (1,0,2).

Cf. A118434.

Cf. A144182, A000587.

Vec((1+2*x^2+4*x^3)/(1-x-2*x^3) + O(x^40)) \\ Colin Barker, Aug 21 2016

Equals row sums of triangle A144182 and INVERT transform of A118434: (1, 0, 2, 4, -4, 0, -8, -16, 16, 0, 32,...).
From Colin Barker, Aug 21 2016: (Start)
a(n) = a(n-1)+2*a(n-3) for n>3.
G.f.: (1+2*x^2+4*x^3) / (1-x-2*x^3).
(End)

More terms from Alois P. Heinz, May 23 2015

A144183 Triangle read by rows, A144182 * A000012.

Original entry on oeis.org

1, 1, 1, 3, 1, 1, 9, 5, 3, 3, 11, 15, 11, 9, 9, 17, 17, 21, 17, 11, 11, 35, 43, 43, 47, 35, 17, 17, 57, 73, 81, 81, 93, 57, 35, 35, 91, 75, 91, 99, 99, 135, 91, 57, 57, 161, 161, 145, 161, 185, 185, 229, 161, 91, 91, 275, 243, 243, 227, 275, 347, 347, 415, 275, 161, 161

Offset: 0

Gary W. Adamson, Sep 13 2008

Left border = A144181: (1, 1, 3, 9, 11, 17, 35,...) = INVERT transform of A118434. Right border = A144181 shifted.

			First few rows of the triangle =
1;
1, 1;
3, 1, 1;
9, 5, 3, 3;
11, 15, 11, 9, 9;
17, 17, 21, 17, 11, 11;
35, 43, 43, 47, 35, 17, 17;
57, 73, 81, 81, 93, 57, 35, 35;
91, 75, 91, 99, 99, 135, 91, 57, 57;
...
Row 3 = (9, 5, 3, 3) = partial sums from the right of row 3, triangle A144182: (4, 2, 0, 3).

A144182, Cf. A144181, A118434

Triangle read by rows, A144182 * A000012; (equivalent to taking partial row sums

of A144182 starting from the right). A000012 = an infinite lower triangular matrix with all 1's and the rest zeros.

cp's OEIS Frontend

A144181 INVERT transform of A118434, = row sums of triangle A144182.

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