cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A144853 Coefficients in the expansion of the sine lemniscate function.

Original entry on oeis.org

1, 1, 21, 2541, 1023561, 1036809081, 2219782435101, 8923051855107621, 61797392100611962641, 690766390156657904866161, 11839493254591562294152214181, 298556076626963858753929987732701, 10706038142052878970311146962646277721, 530588758323899225681861502684757146635241
Offset: 0

Views

Author

N. J. A. Sloane, Feb 12 2009

Keywords

Comments

Denoted \alpha_n by Lomont and Brillhart on page xii.

Examples

			G.f. = 1 + x + 21*x^2 + 2541*x^3 + 1023561*x^4 + 1036809081*x^5 + ...
		

References

  • J. S. Lomont and J. Brillhart, Elliptic Polynomials, Chapman and Hall, 2001; see p. 87.

Crossrefs

Programs

  • Maple
    for n from 1 to 15 do b[n]:=add(binomial(4*n,4*j+2)*b[j]*b[n-1-j],j=0..n-1);
    a[n]:=(1/3)*add(binomial(4*n-1,4*j+1)*a[j]*b[n-1-j],j=0..n-1); od:
    ta:=[seq(a[n],n=0..15)];
  • Mathematica
    a[ n_] := If[ n < 0, 0, With[ {m = 4 n + 1}, m! SeriesCoefficient[ JacobiSD[ x, 1/2], {x, 0, m}] / (-3)^n]]; (* Michael Somos, Apr 25 2011 *)
    a[ n_] := If[ n < 0, 0, With[ {m = 4 n + 1}, m! SeriesCoefficient[ InverseSeries[ Integrate[ Series[ (1 + x^4 / 12) ^ (-1/2), {x, 0, m + 1}], x]], {x, 0, m}]]]; (* Michael Somos, Apr 25 2011 *)
  • PARI
    {a(n) = my(m); if( n<0, 0, m = 4*n + 1; m! * polcoeff( serreverse( intformal( (1 + x^4 / 12 + x * O(x^m)) ^ (-1/2))), m))}; /* Michael Somos, Apr 25 2011 */
    
  • PARI
    {a(n) = my(A, m); if( n<0, 0, m = 4*n + 1; A = O(x); for( k=0, n, A = x + intformal( intformal( A^3 / 6))); m! * polcoeff( A, m))}; /* Michael Somos, Apr 25 2011 */

Formula

E.g.f.: sl(x) = Sum_{k>=0} (-12)^k * a(k) * x^(4*k + 1) / (4*k + 1)! where sl(x) = sin lemn(x) is the sine lemniscate function of Gauss. - Michael Somos, Apr 25 2011
a(0) = 1, a(n + 1) = (1 / 3) * Sum_{j=0..n} binomial( 4*n + 3, 4*j + 1) * a(j) * b(n - j) where b() is A144849.
G.f.: 1 / (1 - b(1)*x / (1 - b(2)*x / (1 - b(3)*x / ... ))) where b = A187756. - Michael Somos, Jan 03 2013