A144854 Values of n such that the expression sqrt(4!*(n+1) + 1) yields a perfect power.

25, 99, 609, 650, 1189, 3479, 4901, 5429, 11659, 16275, 29469, 38479, 62525, 73814, 78089, 117739, 142449, 201116, 203319, 240199, 328769, 381275, 406900, 504889, 576909, 743775, 839629, 1005731, 1058819, 1183259, 1464709, 1622919, 1960244

Offset: 1

Author

Alexander R. Povolotsky, Sep 22 2008

Keywords

• nonn

Examples

			25 is in the sequence since sqrt(4!*(25+1) + 1) = 25 = 5^2;
99 is in the sequence since sqrt(4!*(99+1) + 1) = 49 = 7^2. - _Jon E. Schoenfield_, Aug 01 2015
		

Crossrefs

Subset of A144065.

Programs

Mathematica

lst = {}; Do[a = Sqrt[4! (n + 1) + 1]; If[IntegerQ@ a && GCD @@ Last /@ FactorInteger@a > 1, AppendTo[lst, n]], {n, 0, 1977428}]; lst (* Robert G. Wilson v, Sep 24 2008 *)

Extensions

More terms from Robert G. Wilson v, Sep 24 2008