cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A269993 Denominators of r-Egyptian fraction expansion for sqrt(1/2), where r = (1,1/2,1/3,1/4,...)

Original entry on oeis.org

2, 3, 9, 74, 8098, 101114070, 10080916639334518, 234737156891222571756748160861129, 104728182461244680288139397973895577148266725366426255244889745185
Offset: 1

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Author

Clark Kimberling, Mar 15 2016

Keywords

Comments

Suppose that r is a sequence of rational numbers r(k) <= 1 for k >= 1, and that x is an irrational number in (0,1). Let f(0) = x, n(k) = floor(r(k)/f(k-1)), and f(k) = f(k-1) - r(k)/n(k). Then x = r(1)/n(1) + r(2)/n(2) + r(3)/n(3) + ... , the r-Egyptian fraction for x.
Guide to related sequences:
r(k) x denominators
1 sqrt(1/2) A069139
1 sqrt(1/3) A144983
1 sqrt(2) - 1 A006487
1 sqrt(3) - 1 A118325
1 tau - 1 A117116
1 1/Pi A006524
1 Pi-3 A001466
1 1/e A006526
1 e - 2 A006525
1 log(2) A118324
1 Euler constant A110820
1 (1/2)^(1/3) A269573
.
1/k sqrt(1/2) A269993
1/k sqrt(1/3) A269994
1/k sqrt(2) - 1 A269995
1/k sqrt(3) - 1 A269996
1/k tau - 1 A269997
1/k 1/Pi A269998
1/k Pi-3 A269999
1/k 1/e A270001
1/k e - 2 A270002
1/k log(2) A270314
1/k Euler constant A270315
1/k (1/2)^(1/3) A270316
.
Using the 12 choices for x shown above (that is, sqrt(1/2) to (1/2)^(1/3)), the denominator sequence of the r-Egyptian fraction for x appears for each of the following sequences (r(k)):
r(k) = 1 (see above)
r(k) = 1/k (see above)
r(k) = 2^(1-k): A270347-A270358
r(k) = 1/Fibonacci(k+1): A270394-A270405
r(k) = 1/prime(k): A270476-A270487
r(k) = 1/k!: A270517-A270527 (A000027 for x = e - 2)
r(k) = 1/(2k-1): A270546-A270557
r(k) = 1/(k+1): A270580-A270591

Examples

			sqrt(1/2) = 1/2 + 1/(2*3) + 1/(3*9) + ...
		

Crossrefs

Programs

  • Mathematica
    r[k_] := 1/k; f[x_, 0] = x; z = 10;
    n[x_, k_] := n[x, k] = Ceiling[r[k]/f[x, k - 1]]
    f[x_, k_] := f[x, k] = f[x, k - 1] - r[k]/n[x, k]
    x = Sqrt[1/2]; Table[n[x, k], {k, 1, z}]
  • PARI
    r(k) = 1/k;
    x = sqrt(1/2);
    f(x, k) = if(k<1, x, f(x, k - 1) - r(k)/n(x, k));
    n(x, k) = ceil(r(k)/f(x, k - 1));
    for(k = 1, 10, print1(n(x, k),", ")) \\ Indranil Ghosh, Mar 27 2017, translated from Mathematica code
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