A152049 Number of conjugacy classes of primitive elements in GF(2^n) which have trace 0.
0, 0, 1, 1, 3, 2, 9, 9, 23, 29, 89, 72, 315, 375, 899, 1031, 3855, 3886, 13797, 12000, 42328, 59989, 178529, 138256, 647969, 859841, 2101143, 2370917, 9204061, 8911060, 34636833, 33556537, 105508927, 168423669, 464635937
Offset: 1
Examples
a(3)=1 because of the two primitive degree 3 polynomials over GF(2), namely t^3+t+1 and t^3+t^2+1, only the former has a zero next-to-highest coefficient. Similarly, a(13)=315, because of half (4096) of the 8192 elements of GF(2^13) have trace 0 and all except 0 (since 1 has trace 1) are primitive, so there are 4095/13=315 conjugacy classes of primitive elements of trace 0.
Crossrefs
Programs
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GAP
a := function(n) local q,k,cnt,x; q:=2^n; k:=GF(2,n); cnt:=0; for x in k do if Trace(k, GF(2), x)=0*Z(2) and Order(x)=q-1 then cnt := cnt+1; fi; od; return cnt/n; end; for n in [1..32] do Print (a(n), ", "); od;
Formula
a(n) = A192211(n)/n. [Joerg Arndt, Jul 03 2011]
Extensions
More terms (13797...8911060) by Joerg Arndt, Jun 26 2011.
More terms (34636833...464635937) by Joerg Arndt, Jul 03 2011.
Comments