A135725 Let d(i) be the i-th digit of the decimal expansion of e = 2.718281828459045235360287471352662..., so that d(0) = 2, d(1) = 7, d(2) = 1, etc. Then a(0) = 2, a(n) = d(d(n)) for n>0.
2, 8, 7, 2, 1, 2, 7, 2, 1, 2, 2, 8, 8, 2, 2, 8, 1, 8, 8, 8, 1, 2, 1, 2, 8, 2, 8, 7, 8, 8, 1, 1, 1, 1, 2, 8, 8, 8, 8, 8, 1, 2, 8, 2, 8, 8, 1, 8, 8, 8, 8, 8, 8, 8, 2, 8, 1, 1, 8, 1, 8, 1, 1, 8, 8, 1, 2, 2, 8, 1, 1, 8, 2, 8, 8, 8, 8, 2, 8, 8, 8, 2, 8, 8, 7, 8, 2, 1, 7, 8, 2, 8, 1, 8, 7, 1, 1, 2, 1
Offset: 0
Links
- Zak Seidov, Table of n, a(n) for n = 0..999
Crossrefs
Cf. A155912.
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