A162892 Integers n such that the century defined by the interval [100n+1,100n+100] (i.e., the (n+1)-st century) contains exactly three Ormiston prime pairs.

651507, 1057749, 1263729, 1666162, 2527374, 3620083, 3850824, 4925140, 5418973, 8255451, 8300166, 8318772, 8389776, 9829099, 10876176, 11419227, 12195316, 14241925, 15170550, 15864637, 15876420, 16868593, 16892233, 17123505, 18032409

Offset: 1

Author

Ray Chandler and Ki Punches, Jul 16 2009

Keywords

• base
• nonn

Comments

Ormiston pairs must be of form (100n+13,100n+31), (100n+37,100n+73), (100n+79,100n+97).

There cannot be more than three Ormiston prime pairs in a century.

Crossrefs

Cf. A162893.

Programs

PARI

is(n)=isprime(100*n+13) && nextprime(100*n+17)==100*n+31 && isprime(100*n+37) && nextprime(100*n+39)==100*n+73 && isprime(100*n+79) && nextprime(100*n+81)==100*n+97 \\ Charles R Greathouse IV, Mar 07 2016