A165582 Partial sums of A165581.

0, 1, 2, 1, 2, 1, 0, -1, 0, 1, 0, -1, -2, -1, -2, -1, 0, -1, 0, -1, -2, -1, -2, -3, -4, -3, -2, -3, -4, -3, -2, -1, 0, 1, 0, 1, 2, 3, 2, 1, 0, 1, 2, 1, 0, -1, -2, -3, -4, -3, -2, -1, 0, 1, 0, 1, 0, 1, 2, 3, 4, 3, 4, 3, 4, 3, 4, 5, 4, 5, 6, 7, 8, 9, 10, 9, 8, 9, 8, 9, 8, 9, 10, 9, 10, 11, 10

Offset: 0

Author

Antti Karttunen, Sep 22 2009

Keywords

• sign
• easy

Comments

Period 524287. The largest value 658 occurs in four positions: a(184560) = a(184562) = a(339724) = a(339726) = 658. Note that a(262143) = 255 and a(174762) = a(349524) = 510. (Cf. to A165477 and see comments at A165479).

Links

• A. Karttunen, Table of n, a(n) for n = 0..524287

Crossrefs

Positions of zeros: A165583. See also A165584, A165585. Similar sequences: A165472, A165477, A165482, A165575-A165579, A165582, A165587, A165592, A165597.

Programs

PARI

a(n)=sum(k=1,n%524287,kronecker(n,524287)) \\ Charles R Greathouse IV, Aug 06 2012