cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A121153 Numbers k with the property that 1/k can be written in base 3 in such a way that the fractional part contains no 1's.

Original entry on oeis.org

1, 3, 4, 9, 10, 12, 13, 27, 28, 30, 36, 39, 40, 81, 82, 84, 90, 91, 108, 117, 120, 121, 243, 244, 246, 252, 270, 273, 324, 328, 351, 360, 363, 364, 729, 730, 732, 738, 756, 757, 810, 819, 820, 949, 972, 984, 1036, 1053, 1080, 1089, 1092, 1093, 2187
Offset: 1

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Author

Jack W Grahl, Aug 12 2006

Keywords

Comments

Numbers k such that 1/k is in the Cantor set.
A subsequence of A054591. The first member of A054591 which does not belong to this sequence is 146. See A135666.
This is not a subsequence of A005836 (949 belongs to the present sequence but not to A005836). See A170830, A170853.

Examples

			1/3 in base 3 can be written as either .1 or .0222222... The latter version contains no 1's, so 3 is in the sequence.
1/4 in base 3 is .02020202020..., so 4 is in the sequence.
		

Crossrefs

Programs

  • Mathematica
    (* Mma code from T. D. Noe, Feb 20 2010. This produces the sequence except for the powers of 3. *)
    (* Find the length of the periodic part of the fraction: *)
    FracLen[n_] := Module[{r = n/3^IntegerExponent[n, 3]}, MultiplicativeOrder[3, r]]
    (* Generate the fractions and select those that have no 1's: *)
    Select[Range[100000], ! MemberQ[Union[RealDigits[1/#, 3, FracLen[ # ]][[1]]], 1] &]
  • PARI
    is(n,R=divrem(3^logint(n,3),n),S=0)={while(R[1]!=1&&!bittest(S,R[2]), S+=1<M. F. Hasler, Feb 27 2018

Extensions

Extended to 10^5 by T. D. Noe and N. J. A. Sloane, Feb 20 2010
Entry revised by N. J. A. Sloane, Feb 22 2010

A173784 Number of numbers k such that 1/k is in the Cantor set and 3^n <= k < 3^(n+1).

Original entry on oeis.org

1, 2, 4, 6, 9, 12, 18, 23, 28, 34, 42, 49, 61, 68, 80, 91, 103, 111, 128, 138, 156
Offset: 0

Views

Author

T. D. Noe, Feb 24 2010

Keywords

Comments

This sequence gives the length of the rows in the irregular triangle A170952. See A121153 for the values of k.
Showing 1-2 of 2 results.