A173736 a(n) = (10^n + 35)/9 for n>0.
5, 15, 115, 1115, 11115, 111115, 1111115, 11111115, 111111115, 1111111115, 11111111115, 111111111115, 1111111111115, 11111111111115, 111111111111115, 1111111111111115, 11111111111111115, 111111111111111115, 1111111111111111115, 11111111111111111115, 111111111111111111115
Offset: 1
Links
- Vincenzo Librandi, Table of n, a(n) for n = 1..100
- Index entries for linear recurrences with constant coefficients, signature (11,-10).
Crossrefs
Cf. A093135.
Programs
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Magma
[(10^n+35)/9: n in [1..20]]; // Vincenzo Librandi, Jul 05 2012
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Mathematica
CoefficientList[Series[(5-40*x)/((1-x)*(1-10*x)),{x,0,30}],x] (* Vincenzo Librandi, Jul 05 2012 *)
Formula
a(n) = a(n-1) + 10^(n-1) = 10*a(n-1) - 35 with n>0, a(0)=4.
From Vincenzo Librandi, Jul 05 2012: (Start)
G.f.: 5*x*(1-8*x)/((1-x)*(1-10*x)).
a(n) = 11*a(n-1) - 10*a(n-2). (End)
From Elmo R. Oliveira, Jun 18 2025: (Start)
E.g.f.: -4 + exp(x)*(35 + exp(9*x))/9.
a(n) = 5*A093135(n-1). (End)