A175494 a(n) = floor(n^(1/d(n))), where d(n) = number of divisors of n.
1, 1, 1, 1, 2, 1, 2, 1, 2, 1, 3, 1, 3, 1, 1, 1, 4, 1, 4, 1, 2, 2, 4, 1, 2, 2, 2, 1, 5, 1, 5, 1, 2, 2, 2, 1, 6, 2, 2, 1, 6, 1, 6, 1, 1, 2, 6, 1, 3, 1, 2, 1, 7, 1, 2, 1, 2, 2, 7, 1, 7, 2, 1, 1, 2, 1, 8, 2, 2, 1, 8, 1, 8, 2, 2, 2, 2, 1, 8, 1, 2, 3, 9, 1, 3, 3, 3
Offset: 1
Keywords
Links
- T. D. Noe, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
Table[Floor[n^(1/DivisorSigma[0, n])], {n, 100}] (* T. D. Noe, May 14 2013 *)
Extensions
More terms from R. J. Mathar, May 31 2010