A175659 Eight bishops and one elephant on a 3 X 3 chessboard: a(n)= (3^(n+1)-Jacobsthal(n+1))-(3^n-Jacobsthal(n)), with Jacobsthal=A001045.
1, 6, 16, 52, 156, 476, 1436, 4332, 13036, 39196, 117756, 353612, 1061516, 3185916, 9560476, 28686892, 86071596, 258236636, 774753596, 2324348172, 6973219276, 20920007356, 62760721116, 188283561452, 564853480556
Offset: 0
Links
- Vincenzo Librandi, Table of n, a(n) for n = 0..1000
- Index entries for linear recurrences with constant coefficients, signature (4,-1,-6).
Programs
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Magma
I:=[1, 6, 16]; [n le 3 select I[n] else 4*Self(n-1)-Self(n-2)-6*Self(n-3): n in [1..35]]; // Vincenzo Librandi, Jul 21 2013
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Maple
nmax:=24; m:=5; A[5]:= [1,0,1,0,1,0,1,1,1]: A:=Matrix([[0,0,0,0,1,0,0,0,1], [0,0,0,1,0,1,0,0,0], [0,0,0,0,1,0,1,0,0], [0,1,0,0,0,0,0,1,0], A[5], [0,1,0,0,0,0,0,1,0], [0,0,1,0,1,0,0,0,0], [0,0,0,1,0,1,0,0,0], [1,0,0,0,1,0,0,0,0]]): for n from 0 to nmax do B(n):=A^n: a(n):= add(B(n)[m,k],k=1..9): od: seq(a(n), n=0..nmax);
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Mathematica
CoefficientList[Series[(1 + 2 x - 7 x^2) / (1 - 4 x + x^2 + 6 x^3), {x, 0, 40}], x] (* Vincenzo Librandi, Jul 21 2013 *)
Formula
G.f.: (1+2*x-7*x^2)/(1-4*x+x^2+6*x^3).
a(n) = 4*a(n-1)-a(n-2)-6*a(n-3) with a(0)=1, a(1)=6 and a(2)=16.
a(n) = (-2*(-1)^n)/3-2^n/3+2*3^n. [Colin Barker, Oct 07 2012]
Comments