A176113 Determinant of n X n matrix whose (i,j)-th element is (i+j)^(n-1).

1, -1, -8, 1296, 7962624, -2985984000000, -100306130042880000000, 416336312719673760153600000000, 281633758444745849464726940024832000000000

Offset: 1

Author

Michel Lagneau, Apr 08 2010

Keywords

• sign

Comments

a(n) = A057077(n)*A091868(n-1), signed variant of A091868.

Concerning the general case det((u(i) + v(j))^(n-1) for 1<=i,j<=n and u(1), ...,u(n), v(1), ..., v(n) integers, the reference give the proof that det((u(i) + v(j))^(n-1) = (1/x) *(((n-1)!)^n)*y*z with the following results :

x = 1! * 2!*...(n-1)! ;

y = (u(1) - u(2))*((u(1) - u(3))*....*(u(n-1) - u(n)) ;

z = (v(n) - v(n-1))*((v(n) - v(n-2))*....*(v(2) - v(1)).

If the (i,j)-th element is (i+j)^(n-1), then u(i) = i and v(j) = n+1-j. Finally, det(n X n) = ((-1)^p)* (n!)^(n+1) with n = 2p + 1 or n=2p.

Examples

			a(3) = determinant(M_3) = -8 where M_3 is the matrix
[4  9   16]
[9  16  25]
[16 25  36]
		

References

• J. M. Monier, Algebre & geometrie, Dunod (1996), p.216.

Crossrefs

Cf. A091868.

Programs

Mathematica

a[n_] = ((-1)^((n - Mod[n, 2])/2))*((n - 1)!)^n; Table[a[n], {n, 9}] (* from Jean-François Alcover, Aug 31 2011 *)

Formula

a(n) = (-1)^floor(n/2)* ((n-1)!)^n.