cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A245118 G.f. satisfies: A(x) = 1 + x*A(x)^3 / (A(x) - x*A'(x)).

Original entry on oeis.org

1, 1, 3, 15, 103, 879, 8799, 99711, 1250175, 17077215, 251414175, 3958086015, 66245028447, 1173340901695, 21914481618591, 430320455540223, 8861927054203743, 190989549802914495, 4299479144808402975, 100927457271249951615, 2466702562122306371295, 62678175995432599506495
Offset: 0

Views

Author

Paul D. Hanna, Jul 27 2014

Keywords

Examples

			G.f.: A(x) = 1 + x + 3*x^2 + 15*x^3 + 103*x^4 + 879*x^5 + 8799*x^6 +...
The table of coefficients of x^k in A(x)^n begin:
n=1: [1,  1,  3,  15,  103,   879,   8799,   99711,  1250175, ...]
n=2: [1,  2,  7,  36,  245,  2054,  20199,  225384,  2789545, ...]
n=3: [1,  3, 12,  64,  435,  3597,  34806,  382590,  4674405, ...]
n=4: [1,  4, 18, 100,  683,  5592,  53340,  577960,  6971325, ...]
n=5: [1,  5, 25, 145, 1000,  8136,  76650,  819350,  9758835, ...]
n=6: [1,  6, 33, 200, 1398, 11340, 105730, 1116024, 13129335, ...]
n=7: [1,  7, 42, 266, 1890, 15330, 141736, 1478856, 17191251, ...]
n=8: [1,  8, 52, 344, 2490, 20248, 186004, 1920552, 22071459, ...]
n=9: [1,  9, 63, 435, 3213, 26253, 240069, 2455893, 27918000, ...]
n=10:[1, 10, 75, 540, 4075, 33522, 305685, 3102000, 34903110, ...]; ...
in which the diagonals illustrate the relation
[x^n] A(x)^(n+1) = (n+1) * [x^(n-1)] A(x)^(n+2) for n>=1
as follows:
[x^1] A(x)^2 = 2 = 2*[x^0] A(x)^3 = 2*1 ;
[x^2] A(x)^3 = 12 = 3*[x^1] A(x)^4 = 3*4 ;
[x^3] A(x)^4 = 100 = 4*[x^2] A(x)^5 = 4*25 ;
[x^4] A(x)^5 = 1000 = 5*[x^3] A(x)^6 = 5*200 ;
[x^5] A(x)^6 = 11340 = 6*[x^4] A(x)^7 = 6*1890 ;
[x^6] A(x)^7 = 141736 = 7*[x^5] A(x)^8 = 7*20248 ;
[x^7] A(x)^8 = 1920552 = 8*[x^6] A(x)^9 = 8*240069 ;
[x^8] A(x)^9 = 27918000 = 9*[x^7] A(x)^10 = 9*3102000 ; ...
RELATED SERIES.
Also, from the above table we can generate A182304:
[1/1, 2/2, 12/3, 100/4, 1000/5, 11340/6, 141736/7, 1920552/8, ...]
= [1, 1, 4, 25, 200, 1890, 20248, 240069, 3102000, 43226590, ...];
the g.f. of A182304 begins:
G(x) = x + x^2 + 4*x^3 + 25*x^4 + 200*x^5 + 1890*x^6 + 20248*x^7 +...
where G(x) = x + d/dx G(x)^3/3 and G(x) = A(G(x)).
		

Crossrefs

Programs

  • PARI
    /* From [x^n] A(x)^(n+1) = (n+1) * [x^(n-1)] A(x)^(n+2): */
    {a(n)=local(A=[1, 1]); for(i=2, n, A=concat(A, 0); A[#A]=((#A)*Vec(Ser(A)^(#A+1))[#A-1]-Vec(Ser(A)^(#A))[#A])/(#A)); A[n+1]}
    for(n=0,30,print1(a(n),", "))
    
  • PARI
    /* From A(x) = 1 +  x*A(x)^3 / (A(x) - x*A'(x)): */
    {a(n)=local(A=1+x); for(i=1, n, A = 1 + x*A^3/(A - x*A' +x*O(x^n))); polcoeff(A,n)}
    for(n=0,30,print1(a(n),", "))

Formula

G.f. A(x) satisfies:
(1) [x^n] A(x)^(n+1) = (n+1) * [x^(n-1)] A(x)^(n+2) for n>=1.
(2) A(x) = x/Series_Reversion(G(x)) where G(x) = x + d/dx G(x)^3/3 is the g.f. of A182304; thus, G(x) = A(G(x)).
a(n) ~ c * n! * n^4, where c = 0.005428317993266202636748034138... (same as for A177384). - Vaclav Kotesovec, Jul 28 2014

A177383 G.f. satisfies: [x^n] A(x)^(n+1) = [x^n] A(x)^(n+2) for n>1 with A'(0)=A(0)=1.

Original entry on oeis.org

1, 1, -3, 18, -145, 1398, -15330, 186004, -2455893, 34903110, -529903726, 8547005820, -145847288730, 2624318836412, -49658727391620, 985921121129832, -20496980960236365, 445413655950148710, -10100793273684125430
Offset: 0

Views

Author

Paul D. Hanna, May 15 2010

Keywords

Examples

			G.f.: A(x) = 1 + x - 3*x^2 + 18*x^3 - 145*x^4 + 1398*x^5 +...
Coefficients in the initial powers of A(x) begin:
[1,. 1, -3,. 18,. -145,. 1398,. -15330,. 186004,. -2455893,...];
[1,. 2, -5,. 30,. -245,. 2398,. -26670,. 327740,. -4376445,...];
[1,. 3,(-6), 37,. -309,. 3081,. -34806,. 433470,. -5855301,...];
[1,. 4,(-6),(40), -345,. 3516,. -40398,. 510120,. -6971325,...];
[1,. 5, -5, (40),(-360), 3761,. -43995,. 563460,. -7790675,...];
[1,. 6, -3,. 38, (-360),(3864), -46049,. 598266,. -8368635,...];
[1,. 7,. 0,. 35,. -350, (3864),(-46928), 618465,. -8751225,...];
[1,. 8,. 4,. 32,. -334,. 3792, (-46928),(627264), -8976609,...];
[1,. 9,. 9,. 30,. -315,. 3672,. -46284, (627264),(-9076320),...];
[1, 10, 15,. 30,. -295,. 3522,. -45180,. 620560, (-9076320),...];
where the above terms in parenthesis illustrate the property
that the coefficients of x^n in A(x)^(n+1) and A(x)^(n+2) are equal.
Also, the same terms derive A177384(n) = [x^n] A(x)^(n+1)/(n+1):
[1, 1, -2, 10, -72, 644, -6704, 78408, -1008480, 14065744, ...]
where g.f. G(x) of A177384 satisfies 1/x*d/dx[xG(x)]^2/2 = x+d/dx xG(x):
d/dx x*G(x) = 1 + 2*x - 6*x^2 + 40*x^3 - 360*x^4 + 3864*x^5 -...
d/dx [x*G(x)]^2/2 = x + 3*x^2 - 6*x^3 + 40*x^4 - 360*x^5 + 3864*x^6 -...
		

Crossrefs

Programs

  • PARI
    {a(n)=local(G=1+x+x*O(x^n),H);for(i=1,n,G=1+x/(G+x*deriv(G)+x*O(x^n))); H=x/serreverse(x*G);polcoeff(H,n)}
    for(n=0,20,print1(a(n),", "))
    
  • PARI
    /* From A(x) = 1 + x*(A(x) - x*A'(x)) / A(x)^3 : */
    {a(n)=local(A=1+x+x*O(x^n));for(i=1,n,A=1+x*(A-x*A')/(A^3 +x*O(x^n)));polcoeff(A,n)}
    for(n=0,20,print1(a(n),", "))

Formula

G.f. satisfies: A(x) = 1 + x * (A(x) - x*A'(x)) / A(x)^3. - Paul D. Hanna, Aug 04 2014
Let G(x) be the g.f. of A177384, then
. a(n) = [x^n] G(x)^(-n+1)/(-n+1) for n>1,
. A(x) = G(x/A(x)) so that A(x) = x/Series_Reversion(x*G(x))
where G(x) = 1 + x/(G(x) + x*G'(x)).
a(n) ~ c * (-1)^(n+1) * n! * n^4, where c = 0.0147556981601927885048672335828437... (same as for A182304). - Vaclav Kotesovec, Jul 28 2014
a(n) / A177384(n) ~ exp(1). - Vaclav Kotesovec, Mar 06 2020
Showing 1-2 of 2 results.