A180468 Numbers n such that n/k is an integer. n=(x_1 x_2 ... x_r) where x_i are digits of n, k = x_1^r + x_2^(r-1) + ... + x_r^1.

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 18, 20, 24, 48, 50, 100, 102, 108, 110, 111, 112, 114, 117, 120, 130, 132, 135, 155, 164, 200, 204, 208, 221, 224, 240, 243, 336, 414, 476, 500, 512, 762

Offset: 1

Author

Ctibor O. Zizka, Sep 06 2010

Keywords

• easy
• nonn
• base

Comments

n=48, k=4^2+8^1=24, n/k=2 so 48 belongs to the sequence. For binary numbers we have the sequence of n-s such that n/(1-s counting sequence) is an integer, this is A049445.

Links

• Harvey P. Dale, Table of n, a(n) for n = 1..1000

Crossrefs

Cf. A049445

Programs

Mathematica

Join[{0},Select[Range[800],Divisible[#,Total[IntegerDigits[#]^ Reverse[ Range[ IntegerLength[ #]]]]]&]] (* Harvey P. Dale, Dec 03 2018 *)