cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A182337 List of positive integers whose prime tower factorization, as defined in comments, does not contain the prime 3.

Original entry on oeis.org

1, 2, 4, 5, 7, 10, 11, 13, 14, 16, 17, 19, 20, 22, 23, 25, 26, 28, 29, 31, 32, 34, 35, 37, 38, 41, 43, 44, 46, 47, 49, 50, 52, 53, 55, 58, 59, 61, 62, 65, 67, 68, 70, 71, 73, 74, 76, 77, 79, 80, 82, 83, 85, 86, 89, 91, 92, 94, 95, 97, 98, 100, 101, 103, 106
Offset: 1

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Author

Patrick Devlin, Apr 25 2012

Keywords

Comments

The prime tower factorization of a number can be recursively defined as follows:
(0) The prime tower factorization of 1 is itself
(1) To find the prime tower factorization of an integer n>1, let n = p1^e1 * p2^e2 * ... * pk^ek be the usual prime factorization of n. Then the prime tower factorization is given by p1^(f1) * p2^(f2) * ... * pk^(fk), where fi is the prime tower factorization of ei.
As an alternative definition, let I(n) be the indicator function for the set of positive integers whose prime tower factorization does not contain a 3. Then I(n) is the multiplicative function satisfying I(p^k) = I(k) for p prime not equal to 3, and I(3^k) = 0.

Crossrefs

Cf. A182318.

Programs

  • Maple
    # The integer n is in this sequence if and only if
    # containsPrimeInTower(3, n) returns false
    containsPrimeInTower:=proc(q, n) local i, L, currentExponent; option remember;
    if n <= 1 then return false: end if;
    if type(n/q, integer) then return true: end if;
    L := ifactors(n)[2];
    for i to nops(L) do currentExponent := L[i][2];
      if containsPrimeInTower(q, currentExponent) then return true: end if
    end do;
    return false:
    end proc:
    select(x-> not containsPrimeInTower(3,x), [$1..120])[];
  • Mathematica
    indic[1] = 1; indic[n_] := indic[n] = Switch[f = FactorInteger[n], {{3, }}, 0, {{, }}, indic[f[[1, 2]] ], , Times @@ (indic /@ (Power @@@ f))]; Select[Range[120], indic[#] == 1&] (* Jean-François Alcover, Feb 25 2018 *)