A182592 Number of prime factors of form cn+1 for numbers 5^n-1.

1, 1, 1, 2, 2, 1, 1, 2, 3, 1, 2, 1, 3, 3, 2, 2, 3, 3, 3, 3, 4, 2, 3, 4, 3, 4, 3, 3, 5, 2, 3, 3, 4, 6, 3, 3, 6, 3, 5, 2, 6, 2, 3, 4, 4, 1, 2, 1, 6, 5, 3, 3, 7, 5, 3, 2, 5, 2, 7, 3, 5, 6, 4, 4, 7, 5, 8, 6, 8, 2, 3, 3, 6, 5, 5, 3, 7, 3, 4, 2, 6, 3, 3, 3, 6, 4, 4, 6, 5, 3, 2, 5, 4, 7, 5, 3, 4, 5, 7, 3, 10, 4, 5, 8, 6, 5, 2, 4, 7, 3, 6, 8, 5, 10, 2, 3, 6, 5, 7

Offset: 2

Author

Seppo Mustonen, Nov 22 2010

Keywords

• nonn

Examples

			For n=10, 5^n-1=9765624=2^3*3*11*71*521 has three prime factors of the form cn+1, namely 11=n+1, 71=7n+1, 521=52n+1. Thus a(10)=3.
		

Links

• S. Mustonen, On prime factors of numbers m^n+-1
• Seppo Mustonen, On prime factors of numbers m^n+-1 [Local copy]

Programs

Mathematica

m = 5; n = 2; nmax = 120;
While[n <= nmax, {l = FactorInteger[m^n - 1]; s = 0;
     For[i = 1, i <= Length[l],
      i++, {p = l[[i, 1]];
       If[IntegerQ[(p - 1)/n] == True, s = s + l[[i, 2]]];}];
     a[n] = s;} n++;];
Table[a[n], {n, 2, nmax}]
Table[Count[FactorInteger[5^n-1][[All,1]],?(Mod[#,n]==1&)],{n,2,130}] (* _Harvey P. Dale, Dec 11 2016 *)