A182995 Sum of parts of the n-th subsection of the head of the last section of the set of partitions of any odd integer >= 2n+1.

3, 7, 18, 44, 82, 158, 303, 507, 873, 1470, 2354, 3756, 5923, 9065, 13815, 20824, 30853, 45365, 66210, 95415, 136696, 194414, 274057, 384136, 535219, 740559, 1019529, 1396212, 1901533, 2577918, 3479291, 4673711, 6253003, 8332767

Offset: 1

Author

Omar E. Pol, Feb 06 2011

Keywords

• nonn

Comments

The last section of the set of partitions of 2n+1 contains n subsections.

Also first differences of A182737. - Omar E. Pol, Mar 03 2011

Examples

			a(5)=82 because the 5th subsection of the head of the last section of any odd integer >= 11 looks like this:
(11 . . . . . . . . . . )
( 6 . . . . . 5 . . . . )
( 7 . . . . . . 4 . . . )
( 8 . . . . . . . 3 . . )
( 4 . . . 4 . . . 3 . . )
( 5 . . . . 3 . . 3 . . )
.                  (2 . )
.                  (2 . )
.                  (2 . )
.                  (2 . )
.                  (2 . )
.                  (2 . )
.                  (2 . )
.                  (2 . )
There are 21 parts whose sum is 11+6+5+7+4+8+3+4+4+3+5+3+3+2+2+2+2+2+2+2+2 = 11*6 + 2*8 = 82, so a(5) = 82.
		

Crossrefs

Cf. A135010, A138880, A182737, A182743, A182983, A182993, A182994.

Formula

a(n) = A138880(2n+1) - A138880(2n-1).

Extensions

a(17) corrected and more terms from Omar E. Pol, Mar 03 2011.

a(12) corrected by Georg Fischer, Aug 31 2020