A185617 Least m for which A185615(n) divides A000201(A185615(n))^m.

1, 2, 2, 2, 2, 3, 2, 5, 8, 2, 5, 5, 3, 8, 5, 4, 2, 5, 2, 3, 4, 2, 13, 7, 4, 9, 4, 2, 4, 3, 10, 2, 6, 6, 6, 8, 2, 17, 6, 11, 10, 4, 9, 8, 6, 4, 2, 6, 11, 10, 4, 2, 8, 7, 5, 6, 10, 11, 6, 3, 6, 8, 5, 5, 4, 7, 4, 11, 5, 2, 6, 11, 8, 5, 4, 4, 3, 8, 11

Offset: 1

Author

Paul D. Hanna and Sean A. Irvine, Jan 31 2011

Keywords

• nonn

Comments

Is m always <= n?

If A185615(n) = p_1^{e_1} * p_2^{e_2} * ... * p_r^{e_r}, then m <= max{e_1,e_2,...,e_r}.

Crossrefs

Cf. A000201, A185615, A185616