cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A186009 Length of Collatz dropping time patterns in A186008.

Original entry on oeis.org

1, 1, 1, 2, 3, 7, 12, 30, 85, 173, 476, 961, 2652, 8045, 17637, 51033, 108950, 312455, 663535, 1900470, 5936673, 13472296, 39993895, 87986917, 257978502, 820236724, 1899474678, 5723030586, 12809477536, 38036848410, 84141805077, 248369601964
Offset: 1

Views

Author

T. D. Noe, Feb 09 2011

Keywords

Comments

This is A100982 with 1 prepended.

Crossrefs

A260591 a(n) is the number of odd numbers k < 2^n such that A260590(k) = n.

Original entry on oeis.org

0, 1, 0, 1, 2, 0, 3, 7, 0, 12, 0, 30, 85, 0, 173, 476, 0, 961, 0, 2652, 8045, 0, 17637, 51033, 0, 108950, 312455, 0, 663535, 0, 1900470, 5936673, 0, 13472296, 39993895, 0, 87986917, 0, 257978502, 820236724, 0, 1899474678, 5723030586, 0, 12809477536, 38036848410, 0, 84141805077, 0, 248369601964
Offset: 1

Views

Author

Joseph K. Horn, O. Praem, and Robert G. Wilson v, Jul 29 2015

Keywords

Comments

a(n) is either 0 or about c^(n-1) with c = log(3)/log(2).
Nonzero values give A100982. - Ruud H.G. van Tol, Nov 25 2021
A close variant of this sequence, that starts at offset 0, but with a(0)=0 and a(1)=1, maps it to the count of dropping patterns of 2^n+c(2^n), with the c(2^n) as mentioned with A177789. The positions of the zeros of that variant sequence might be a close variant of A054414, again with a(0)=0 (not properly checked yet). - Ruud H.G. van Tol, Nov 28 2021
It appears that the proportion of zeros is 1-log(2)/log(3) = 36.907...%. - Jesse Randall, Oct 10 2024

Examples

			a(1) = 0 since there exists no odd number whose msa is 1;
a(2) = 1 since there is only one odd number, 5 with k=2 2k+1, with k less than 2^2 whose msa is 2;
a(3) = 0 since there exists no odd number whose msa is 3;
a(4) = 1 since there is only one number, 1, less than 2^(4+1) whose msa is 4;
a(5) = 2 since there are two numbers, 11 & 23, less than 2^(4+1) whose msa is 4; etc.
		

Crossrefs

Programs

  • Mathematica
    msa[n_] := If[ OddQ@ n, (3n + 1)/2, n/2]; f[n_] := Block[{k = 2n + 1}, Length@ NestWhileList[ msa@# &, k, # >= k &] - 1]; g[n_] := Length@ Select[ Range[ 2^(n - 1)], f@# == n &]; Array[ g, 20]

Extensions

a(31) onwards from Jesse Randall, Sep 09 2024
Showing 1-2 of 2 results.