A187812 a(n) is the smallest prime(m) such that the interval (prime(m)*n, prime(m+1)*n) contains exactly four primes.
89, 23, 13, 23, 17, 5, 5, 5, 5, 11, 11, 71, 2, 2, 2, 2, 29, 2, 101, 59, 2, 107, 107, 239, 197, 71, 419, 107, 197, 347, 311, 179, 281, 827, 1277, 269, 827, 569, 1481, 1667, 1031, 1019, 617, 2081, 4337, 5651, 3767, 641, 3119, 2789, 2999, 11699, 4241, 8219, 4127
Offset: 2
Keywords
Examples
Let n=6, and consider intervals of the form (6*prime(m), 6*prime(m+1)). For 2, 3, 5, ..., the intervals (12,18), (18,30), (30,42), (42,66), (66,78), (78,102), (102,114)... contain 2, 3, 3, 5, 3, 5, 4,... primes. Hence the smallest such prime is 17.
Links
- Alois P. Heinz, Table of n, a(n) for n = 2..100
Formula
lim a(n) = infinity, as n goes to infinity.
Comments