cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A193826 Expansion of psi(x^2) * phi(x^7) / (f(-x) * f(-x^7)) in powers of x where phi(), psi(), f() are Ramanujan theta functions.

Original entry on oeis.org

1, 1, 3, 4, 7, 10, 17, 26, 38, 57, 81, 114, 161, 224, 309, 419, 569, 759, 1011, 1336, 1757, 2296, 2981, 3855, 4956, 6344, 8087, 10272, 12994, 16367, 20561, 25723, 32086, 39902, 49484, 61182, 75439, 92791, 113821, 139294, 170073, 207187, 251853
Offset: 0

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Author

Michael Somos, Aug 06 2011

Keywords

Comments

Ramanujan theta functions: f(q) (see A121373), phi(q) (A000122), psi(q) (A010054), chi(q) (A000700).

Examples

			G.f. = 1 + x + 3*x^2 + 4*x^3 + 7*x^4 + 10*x^5 + 17*x^6 + 26*x^7 + 38*x^8 + ...
G.f. = 1/q + q^11 + 3*q^23 + 4*q^35 + 7*q^47 + 10*q^59 + 17*q^71 + 26*q^83 + ...
		

Crossrefs

Cf. A102314.

Programs

  • Mathematica
    a[ n_] := SeriesCoefficient[ QPochhammer[ x, x^2] QPochhammer[ x^7, x^14], {x, 0, 4 n}];
    a[ n_] := SeriesCoefficient[ EllipticTheta[ 3, 0, x^7] EllipticTheta[ 2, 0, x] / (2 x^(1/4) QPochhammer[ x] QPochhammer[ x^7]), {x, 0, n}];
    a[ n_] := SeriesCoefficient[ QPochhammer[ x^14, x^28]^2 / (QPochhammer[ x, x^2] QPochhammer[ x^2, x^4]^2 QPochhammer[ x^7, x^14]^3), {x, 0, n}];
  • PARI
    {a(n) = my(A); if( n<0, 0, A = x * O(x^n); polcoeff( eta(x^4 + A)^2 * eta(x^14 + A)^5 / (eta(x + A) * eta(x^2 + A) * eta(x^7 + A)^3* eta(x^28 + A)^2), n))};

Formula

Expansion of chi(-x^14)^2 / (chi(-x) * chi(-x^2)^4 * chi(-x^7)^3 ) in powers of x where chi() is a Ramanujan theta function.
Expansion of q^(1/12) * eta(q^4)^2 * eta(q^14)^5 / (eta(q) * eta(q^2) * eta(q^7)^3* eta(q^28)^2) in powers of q.
Euler transform of period 28 sequence [ 1, 2, 1, 0, 1, 2, 4, 0, 1, 2, 1, 0, 1, 0, 1, 0, 1, 2, 1, 0, 4, 2, 1, 0, 1, 2, 1, 0, ...].
a(n) = A102314(4*n).
a(n) ~ exp(4*Pi*sqrt(n/21)) / (2^(5/2) * 21^(1/4) * n^(3/4)). - Vaclav Kotesovec, Nov 15 2017