A194094 Expansion of (2/Pi)*elliptic_E(k) in powers of q.
1, -4, 20, -64, 164, -392, 896, -1920, 3908, -7684, 14632, -27072, 48896, -86408, 149760, -255104, 427652, -706568, 1152020, -1855296, 2954056, -4654080, 7260288, -11221632, 17194496, -26131980, 39409960, -59003008, 87728640, -129586568, 190226176, -277587456, 402779396, -581276160, 834539560, -1192216320
Offset: 0
Keywords
Examples
E(k(q)) = 1 - 4*q + 20*q^2 - 64*q^3 + 164*q^4 - 392*q^5 + 896*q^6 - 1920*q^7 +- ...
Links
- Robert Israel, Table of n, a(n) for n = 0..2000
Programs
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Maple
N:= 100: # to get a(0) to a(N) t3:= curry(JacobiTheta3,0): t4:= curry(JacobiTheta4,0): Dq:= f -> q*diff(f,q): E1:= t3(q)^2: E2a:= - 2*(t4(q)/t3(q))^2: E2b:= t4(q)^(-2): S1:= series(E1,q,N+1): S2a:= series(E2a,q,N+1): S2b:= series(Dq(series(E2b,q,N+1)),q,N+1): S:= series(S1+S2a*S2b,q,N+1): seq(coeff(S,q,j),j=0..N); # Robert Israel, Sep 02 2015
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Mathematica
a[ n_] := With[ {m = InverseEllipticNomeQ @ q}, SeriesCoefficient[ EllipticE[m] / (Pi/2), {q, 0, n}]] (* Michael Somos, Jan 24 2012 *) a[ n_] := SeriesCoefficient[ Hypergeometric2F1[ -1/2, 1/2, 1, ModularLambda[ Log[q] / (Pi I)]], {q, 0, n}] (* Michael Somos, Jan 24 2012 *) nmax = 30; dtheta = D[Normal[Series[EllipticTheta[3, 0, x], {x, 0, nmax}]], x]; CoefficientList[Series[(EllipticTheta[4, 0, x]^4 * EllipticTheta[3, 0, x] + 4*x*dtheta) / EllipticTheta[3, 0, x]^3, {x, 0, nmax}], x] (* Vaclav Kotesovec, Apr 10 2018 *) nmax = 30; CoefficientList[4 q D[Log[EllipticTheta[2,0,q]+O[q]^nmax],q]/(EllipticTheta[3,0,q]+O[q]^nmax)^2,q] (* Mamuka Jibladze, Jun 02 2025 *)
Formula
Expansion of theta_3(q)^2 - 2 * (theta_4(q) / theta_3(q))^2 * Dq ( theta_4(q)^-2 ) = theta_3(q)^2 + 4 Dq (theta_4(q)) / (theta_4(q) * theta_3(q)^2) in powers of q where Dq (f) := q * df/dq. - Michael Somos, Jan 24 2012
Expansion of (T4^4 * T3 + 4*q * d/dq T3) / T3^3 where T3 = theta_3(q) and T4 = theta_4(q). - Joerg Arndt, Sep 02 2015
a(n) ~ (-1)^n * exp(Pi*sqrt(2*n)) / (Pi * 2^(9/4) * n^(3/4)). - Vaclav Kotesovec, Oct 06 2019
Expansion of 4 * Dq(theta_2(q))/(theta_2(q) * theta_3(q)^2) in powers of q where Dq(f):= q*df/dq. - Mamuka Jibladze, Jun 02 2025
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