A195269 Smallest n such that 3^n contains n consecutive 0's in its decimal representation.
10, 35, 148, 332, 540, 540, 7722, 22793, 107189, 107189, 513335, 1847534, 5756981, 32023025, 82011444
Offset: 1
Links
- Programming contest in Zealint's blog (in Russian)
Programs
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Python
def A195269(n): m, s = 1, '0'*n for i in range(1,10**9): m *= 3 if s in str(m): return i return "search limit reached." # Chai Wah Wu, Dec 11 2014
Extensions
a(15) from Bert Dobbelaere, Mar 20 2019
Comments