A195555
Hypotenuses of primitive Pythagorean triples in A195553 and A195554.
Original entry on oeis.org
13, 701, 18901, 254813, 13741001, 370497401, 4994844413, 269351100901, 7262490035501, 97908939928813, 5279820266120401, 142359329305393201, 1919211035489748013, 103495036587140999501, 2790527565781827490501, 37620374619761100622013
Offset: 1
A195500
Denominators a(n) of Pythagorean approximations b(n)/a(n) to sqrt(2).
Original entry on oeis.org
3, 228, 308, 5289, 543900, 706180, 1244791, 51146940, 76205040, 114835995824, 106293119818725, 222582887719576, 3520995103197240, 17847666535865852, 18611596834765355, 106620725307595884, 269840171418387336, 357849299891217865
Offset: 1
For r=sqrt(2), the first five fractions b(n)/a(n) can be read from the following five primitive Pythagorean triples (a(n), b(n), c(n)) = (A195500, A195501, A195502):
(3,4,5); |r - b(1)/a(1)| = 0.08...
(228,325,397); |r - b(2)/a(2)| = 0.011...
(308,435,533); |r - b(3)/a(3)| = 0.0018...
(5289,7480,9161); |r - b(4)/a(4)| = 0.000042...
(543900,769189,942061); |r - b(5)/a(5)| = 0.0000003...
-
Shiu := proc(r,n)
t := r+sqrt(1+r^2) ;
cf := numtheory[cfrac](t,n+1) ;
mn := numtheory[nthconver](cf,n) ;
(mn-1/mn)/2 ;
end proc:
A195500 := proc(n)
Shiu(sqrt(2),n) ;
denom(%) ;
end proc: # R. J. Mathar, Sep 21 2011
-
r = Sqrt[2]; z = 18;
p[{f_, n_}] := (#1[[2]]/#1[[
1]] &)[({2 #1[[1]] #1[[2]], #1[[1]]^2 - #1[[
2]]^2} &)[({Numerator[#1], Denominator[#1]} &)[
Array[FromContinuedFraction[
ContinuedFraction[(#1 + Sqrt[1 + #1^2] &)[f], #1]] &, {n}]]]];
{a, b} = ({Denominator[#1], Numerator[#1]} &)[
p[{r, z}]] (* A195500, A195501 *)
Sqrt[a^2 + b^2] (* A195502 *)
A195553
Denominators a(n) of Pythagorean approximations b(n)/a(n) to 5/2.
Original entry on oeis.org
5, 260, 7020, 94635, 5103280, 137599280, 1855038645, 100034487540, 2697221086300, 36362467421275, 1960876019662560, 52870927596046560, 712777084536797285, 38437091637391006820, 1036375920040483589580, 13971856374727832955915
Offset: 1
-
r = 5/2; z = 18;
p[{f_, n_}] := (#1[[2]]/#1[[
1]] &)[({2 #1[[1]] #1[[2]], #1[[1]]^2 - #1[[
2]]^2} &)[({Numerator[#1], Denominator[#1]} &)[
Array[FromContinuedFraction[
ContinuedFraction[(#1 + Sqrt[1 + #1^2] &)[f], #1]] &, {n}]]]];
{a, b} = ({Denominator[#1], Numerator[#1]} &)[
p[{r, z}]] (* A195553, A195554 *)
Sqrt[a^2 + b^2] (* A195555 *)
(* Peter J. C. Moses, Sep 02 2011 *)
Showing 1-3 of 3 results.
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