cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A200537 G.f. satisfies: A(x) = exp( Sum_{n>=1} [Sum_{k=0..2*n} A200536(n,k)^2 * x^k] / A(x)^n * x^n/n ), where A200536(n,k) is the coefficient of x^k in (1+3*x+2*x^2)^n.

Original entry on oeis.org

1, 1, 9, 13, 40, 72, 144, 252, 432, 720, 1152, 1872, 2880, 4608, 6912, 10944, 16128, 25344, 36864, 57600, 82944, 129024, 184320, 285696, 405504, 626688, 884736, 1363968, 1916928, 2949120, 4128768, 6340608, 8847360, 13565952, 18874368, 28901376, 40108032, 61341696, 84934656, 129761280
Offset: 0

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Author

Paul D. Hanna, Nov 18 2011

Keywords

Examples

			G.f.: A(x) = 1 + x + 9*x^2 + 13*x^3 + 40*x^4 + 72*x^5 + 144*x^6 +...
The logarithm of the g.f. A(x) equals the series:
log(A(x)) = (1 + 3^2*x + 2^2*x^2)/A(x) * x +
(1 + 6^2*x + 13^2*x^2 + 12^2*x^3 + 4^2*x^4)/A(x)^2 * x^2/2 +
(1 + 9^2*x + 62^2*x^2 + 63^2*x^3 + 66^2*x^4 + 36^2*x^5 + 8^2*x^6)/A(x)^3 * x^3/3 +
(1 + 12^2*x + 62^2*x^2 + 180^2*x^3 + 321^2*x^4 + 360^2*x^5 + 248^2*x^6 + 96^2*x^7 + 16^2*x^8)/A(x)^4 * x^4/4 +
(1 + 15^2*x + 100^2*x^2 + 390^2*x^3 + 985^2*x^4 + 1683^2*x^5 + 1970^2*x^6 + 1560^2*x^7 + 800^2*x^8 + 240^2*x^9 + 32^2*x^10)/A(x)^5 * x^5/5 +...
which involves the squares of coefficients A200536(n,k) in (1+3*x+2*x^2)^n.
		

Crossrefs

Programs

  • Mathematica
    CoefficientList[Series[(1+x)*(1+x^2)*(1+4*x^2)*(1+4*x^3) / (1-2*x^2)^2, {x, 0, 40}], x] (* Vaclav Kotesovec, Feb 11 2015 *)
    Flatten[{1,1,9,13,40,Table[FullSimplify[9 * 2^(n/2-4) * (-8 - 7*Sqrt[2] + 4*n + 3*Sqrt[2]*n + (-1)^(n+1)*(8 - 7*Sqrt[2] + (-4 + 3*Sqrt[2])*n))],{n,5,40}]}] (* Vaclav Kotesovec, Feb 11 2015 *)
  • PARI
    {a(n)=polcoeff((1+x)*(1+x^2)*(1+4*x^2)*(1+4*x^3) / ((1-2*x^2)^2+x*O(x^n)),n)}
    
  • PARI
    {a(n)=local(A=1+x);for(i=1,n,A=exp(sum(m=1, n, sum(k=0, n, polcoeff((1+3*x+2*x^2+x*O(x^k))^m, k)^2 *x^k) *x^m/(A+x*O(x^n))^m/m)+x*O(x^n)));polcoeff(A, n)}

Formula

G.f.: (1+x)*(1+x^2)*(1+4*x^2)*(1+4*x^3) / (1-2*x^2)^2.

A251689 G.f. satisfies: A(x) = exp( Sum_{n>=1} [Sum_{k=0..2*n} A200536(n,2*n-k)^2 * x^k] / A(x)^n * x^n/n ), where A200536(n,2*n-k) is the coefficient of x^k in (2+3*x+x^2)^n.

Original entry on oeis.org

1, 4, 9, 37, 40, 153, 144, 468, 432, 1260, 1152, 3168, 2880, 7632, 6912, 17856, 16128, 40896, 36864, 92160, 82944, 205056, 184320, 451584, 405504, 986112, 884736, 2138112, 1916928, 4608000, 4128768, 9879552, 8847360, 21086208, 18874368, 44826624, 40108032, 94961664, 84934656, 200540160
Offset: 0

Views

Author

Paul D. Hanna, Feb 23 2015

Keywords

Examples

			G.f.: A(x) = 1 + 4*x + 9*x^2 + 37*x^3 + 40*x^4 + 153*x^5 + 144*x^6 +...
The logarithm of the g.f. A(x) equals the series:
log(A(x)) = (2^2 + 3^2*x + x^2)/A(x) * x +
(4^2 + 12^2*x + 13^2*x^2 + 6^2*x^3 + x^4)/A(x)^2 * x^2/2 +
(8^2 + 36^2*x + 66^2*x^2 + 63^2*x^3 + 33^2*x^4 + 9^2*x^5 + x^6)/A(x)^3 * x^3/3 +
(16^2 + 96^2*x + 248^2*x^2 + 360^2*x^3 + 321^2*x^4 + 180^2*x^5 + 62^2*x^6 + 12^2*x^7 + x^8)/A(x)^4 * x^4/4 +
(32^2 + 240^2*x + 800^2*x^2 + 1560^2*x^3 + 1970^2*x^4 + 1683^2*x^5 + 985^2*x^6 + 390^2*x^7 + 100^2*x^8 + 15^2*x^9 + x^10)/A(x)^5 * x^5/5 +...
which involves the squares of coefficients A200536(n,2*n-k) in (2+3*x+x^2)^n.
		

Crossrefs

Programs

  • PARI
    {a(n)=polcoeff( (1+4*x)*(1+4*x^2)*(1+x^2)*(1+x^3) / ((1-2*x^2)^2 +x*O(x^n)), n)}
    for(n=0,40,print1(a(n),", "))
    
  • PARI
    {a(n)=local(A=1+x); for(i=1, n, A=exp(sum(m=1, n, sum(k=0, n, polcoeff((2+3*x+x^2+x*O(x^k))^m, k)^2 *x^k) *x^m/(A+x*O(x^n))^m/m)+x*O(x^n))); polcoeff(A, n)}
    for(n=0,40,print1(a(n),", "))

Formula

G.f.: (1+4*x)*(1+4*x^2)*(1+x^2)*(1+x^3) / (1-2*x^2)^2.

A218619 G.f. satisfies: A(x) = exp( Sum_{n>=1} x^n*A(x)^n/n * Sum_{k=0..2*n} A200536(n,k)^2 * x^k * A(x)^(2*k) ), where A200536(n,k) = [x^k] (1 + 3*x + 2*x^2)^n.

Original entry on oeis.org

1, 1, 11, 72, 734, 6994, 74641, 803196, 8989482, 102192197, 1184211027, 13897707080, 165052834584, 1978844990494, 23924151189858, 291313067897212, 3569576082827250, 43981925261314302, 544590342185545146, 6772925262506494672, 84567358373934285042
Offset: 0

Views

Author

Paul D. Hanna, Nov 03 2012

Keywords

Comments

More generally, given that A(x) satisfies:
A(x) = exp( Sum_{n>=1} x^n*A(x)^n/n * Sum_{k=0..2*n} TC(n,k)^2*x^k*A(x)^(2*k) ),
where TC(n,k) = [x^k] (1 + b*x + c*x^2)^n, then A(x) satisfies:
(1) A(x) = (1+x*A(x)^2)*(1+c^2*x^3*A(x)^6)*(1+(b^2-2*c)*x^2*A(x)^4+c^2*x^4*A(x)^8) / (1-2*x^2*A(x)^4)^2.
(2) A(x) = sqrt( (1/x)*Series_Reversion( x*(1-c*x^2)^4 / ((1+x)*(1+c^2*x^3)*(1+(b^2-2*c)*x^2+c^2*x^4))^2 ) ).

Examples

			G.f.: A(x) = 1 + x + 11*x^2 + 72*x^3 + 734*x^4 + 6994*x^5 + 74641*x^6 +...
Let A = g.f. A(x), then the logarithm of the g.f. equals the series:
log(A(x)) = (1 + 3^2*x*A^2 + 2^2*x^2*A^4)*x*A +
(1 + 6^2*x*A^2 + 13^2*x^2*A^4 + 12^2*x^3*A^6 + 4^2*x^4*A^8)*x^2*A^2/2 +
(1 + 9^2*x*A^2 + 33^2*x^2*A^4 + 63^2*x^3*A^6 + 66^2*x^4*A^8 + 36^2*x^5*A^10 + 8^2*x^6*A^12)*x^3*A^3/3 +
(1 + 12^2*x*A^2 + 62^2*x^2*A^4 + 180^2*x^3*A^6 + 321^2*x^4*A^8 + 360^2*x^5*A^10 + 248^2*x^6*A^12 + 96^2*x^7*A^14 + 16^2*x^8*A^16)*x^4*A^4/4 +...
which involves the squares of the trinomial coefficients A200536(n,k):
1;
1, 3, 2;
1, 6, 13, 12, 4;
1, 9, 33, 63, 66, 36, 8;
1, 12, 62, 180, 321, 360, 248, 96, 16;
1, 15, 100, 390, 985, 1683, 1970, 1560, 800, 240, 32; ...
		

Crossrefs

Programs

  • PARI
    /* G.f. A(x) using the squares of the trinomial coefficients */
    {A200536(n, k)=polcoeff((1 + 3*x + 2*x^2)^n, k)}
    {a(n)=local(A=1+x); for(i=1, n, A=exp(sum(m=1, n, sum(k=0, 2*m, A200536(m, k)^2*x^k*(A+x*O(x^n))^(2*k))*x^m*A^m/m))); polcoeff(A, n)}
    for(n=0,30,print1(a(n),", "))
    
  • PARI
    {a(n)=local(A=sqrt(serreverse( x*(1-2*x^2)^4/((1+x)*(1+x^2)*(1+4*x^2)*(1+4*x^3+x*O(x^n)))^2 )/x));polcoeff(A,n)}
    for(n=0,30,print1(a(n),", "))

Formula

G.f. satisfies:
(1) A(x) = (1+x*A(x)^2)*(1+x^2*A(x)^4)*(1+4*x^2*A(x)^4)*(1+4*x^3*A(x)^6) / (1-2*x^2*A(x)^4)^2.
(2) A(x) = sqrt( (1/x)*Series_Reversion( x*(1-2*x^2)^4 / ((1+x)*(1+x^2)*(1+4*x^2)*(1+4*x^3))^2 ) ).
Showing 1-3 of 3 results.