A207036 Numbers k such that the sum of divisors of k is a multiple of 24.
14, 15, 23, 30, 33, 35, 42, 46, 47, 51, 54, 55, 56, 60, 62, 66, 69, 70, 71, 77, 78, 87, 92, 94, 95, 102, 105, 110, 114, 115, 119, 120, 123, 126, 132, 135, 138, 140, 141, 142, 143, 154, 155, 158, 159, 161, 165, 167, 168, 174, 177, 182, 184, 186, 187, 188
Offset: 1
Keywords
Examples
33 is in the sequence because the divisors of 33 are 1, 3, 11, 33 and the sum of divisors of 33 is 1+3+11+33 = A000203(33) = 48 and 48 is a multiple de 24 because 48 divided by 24 gives a positive integer.
Links
- Vincenzo Librandi, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
Select[Range[188], Mod[DivisorSigma[1, #], 24] == 0 &] (* T. D. Noe, Feb 27 2012 *)