A209861 Permutation of nonnegative integers which maps A209641 to A209642.

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 11, 13, 14, 15, 16, 17, 18, 21, 19, 22, 24, 27, 20, 23, 25, 28, 26, 29, 30, 31, 32, 33, 34, 38, 35, 39, 42, 48, 36, 40, 43, 49, 45, 51, 54, 58, 37, 41, 44, 50, 46, 52, 55, 59, 47, 53, 56, 60, 57, 61, 62, 63, 64, 65, 66, 71, 67, 72, 76, 86, 68, 73, 77, 87, 80, 90, 96, 106, 69, 74, 78, 88, 81, 91, 97, 107, 83

Offset: 0

Author

Antti Karttunen, Mar 24 2012

Keywords

• nonn
• look

Comments

Conjecture: For all n, A209861(A054429(n)) = A054429(A209861(n)), i.e. A054429 acts as an homomorphism (automorphism) of the cyclic group generated by this permutation. This implies also a weaker conjecture given in A209860.

The scatterplot graph of the sequence has a nice texture and interesting pattern.

Links

• Antti Karttunen, Table of n, a(n) for n = 0..32767
• Index entries for sequences that are permutations of the natural numbers

Crossrefs

Inverse permutation: A209862. Cf. A209860, A209863, A209864, A209865, A209866, A209867, A209868.

Formula

a(n) = A209640(A209642(n)).