A063511 a(n) = a(floor(sqrt(n))) * 2.
1, 2, 2, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8
Offset: 1
Links
- Kevin Ryde, Table of n, a(n) for n = 1..8192
- Martin Fürer, Faster integer multiplication, Proceedings of the 39th Annual ACM Symposium on Theory of Computing, June 11-13 2007. And in SIAM Journal of Computing, volume 30, number 3, 2009, pages 979-1005. (See size "n" calculation at the start of Algorithm Integer-Multiplication.)
- Index to divisibility sequences
Programs
-
PARI
a(n) = if(n==1,1, 2<
Kevin Ryde, May 11 2020
Formula
a(n) = 2^A211667(n) = 2^ceiling(log_2(log_2(n+1))). - Kevin Ryde, May 11 2020
log_2(n+1) <= a(n) < 2*log_2(n+1). - Charles R Greathouse IV, Nov 30 2024
Extensions
Formula and code by Charles R Greathouse IV moved to A334789 where they apply. - Kevin Ryde, May 11 2020
Comments