cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A214791 Numbers n such that n+8 = A214789(n).

Original entry on oeis.org

17, 23, 26, 37, 53, 67, 83, 137, 157, 163, 167, 173, 193, 197, 223, 283, 293, 367, 373, 383, 467, 487, 523, 547, 577, 613, 643, 673, 683, 727, 787, 853, 863, 887, 907, 937, 1033, 1063, 1093
Offset: 1

Views

Author

Art DuPre, Aug 03 2012

Keywords

Comments

This sequence is disjoint from A214790. It is only a conjecture that this sequence consists of primes except for 26.

Crossrefs

Programs

  • PARI
    is(n)=my(k); while(((Mod([1, 1; 1, 0], n))^k++)[1, 2]!=-8, ); k==n+7 \\ Charles R Greathouse IV, Nov 25 2014

A214795 a(n) is the smallest k>=2 such that n divides Fibonacci(k-1)+21.

Original entry on oeis.org

2, 2, 5, 5, 10, 5, 9, 5, 17, 12, 2, 5, 6, 9, 13, 17, 8, 17, 11, 53, 9, 2, 4, 5, 30, 6, 45, 17, 7, 33, 23, 41, 13, 8, 33, 17, 47, 11, 21, 53, 29, 9, 53, 23, 93, 33, 25, 17, 65, 30, 29, 23, 42, 45, 10, 17, 29, 21, 51, 53
Offset: 1

Views

Author

Art DuPre, Aug 03 2012

Keywords

Comments

The n-th entry a(n) means that a(n) is the index of the first term in A000045+21 which n divides.

Crossrefs

Programs

  • Mathematica
    skdf[n_]:=Module[{k=2},While[!Divisible[Fibonacci[k-1]+21,n],k++];k]; Array[ skdf,60] (* Harvey P. Dale, Nov 25 2017 *)

Extensions

Definition corrected. - R. J. Mathar, Aug 09 2012

A214790 Numbers n such that A214789(n) = n-6.

Original entry on oeis.org

10, 11, 19, 31, 79, 131, 179, 239, 251, 379, 419, 431, 439, 479, 499, 571, 599, 631, 659, 719, 751, 839, 971, 1019, 1091, 1171, 1259, 1319, 1559, 1619, 1759, 1811, 1831, 1879, 1931, 1979
Offset: 1

Views

Author

Art DuPre, Aug 03 2012

Keywords

Comments

It is still a conjecture that 10 is the only nonprime in this sequence. This sequence is disjoint from A214791.

Crossrefs

Programs

  • PARI
    is(n)=my(k); while(((Mod([1, 1; 1, 0], n))^k++)[1, 2]!=-8, ); k==n-7 \\ Charles R Greathouse IV, Nov 25 2014
Showing 1-3 of 3 results.