A218602 Simple self-inverse permutation of natural numbers: after zero, list each block of A213709(n) numbers in reverse order, from A218600(n) to A213710(n-1).

0, 1, 2, 4, 3, 7, 6, 5, 12, 11, 10, 9, 8, 21, 20, 19, 18, 17, 16, 15, 14, 13, 38, 37, 36, 35, 34, 33, 32, 31, 30, 29, 28, 27, 26, 25, 24, 23, 22, 68, 67, 66, 65, 64, 63, 62, 61, 60, 59, 58, 57, 56, 55, 54, 53, 52, 51, 50, 49, 48, 47, 46, 45, 44, 43, 42, 41, 40, 39

Offset: 0

Author

Antti Karttunen, Nov 10 2012

Keywords

• nonn

Comments

This permutation can be used to map between the sequences A179016 and A218616. E.g. A179016(n) = A218616(a(n)) and vice versa: A218616(n) = A179016(a(n)).

Links

• Antti Karttunen, Table of n, a(n) for n = 0..8727
• Index entries for sequences that are permutations of the natural numbers

Crossrefs

Cf. A179016, A218616, A054429, A130918, A054430.

Programs

Scheme

(define (A218602 n) (- (A218600 (A213711 n)) (A218601 n)))

Formula

a(n) = A218600(A213711(n))-A218601(n).