A213732 Positions of even numbers greater than zero in A179016.
3, 5, 8, 11, 13, 16, 17, 22, 25, 26, 30, 33, 35, 36, 37, 39, 42, 43, 47, 50, 52, 53, 54, 55, 58, 65, 66, 69, 72, 73, 77, 80, 82, 83, 84, 85, 88, 95, 96, 98, 101, 108, 109, 110, 114, 115, 116, 117, 118, 121, 123, 126, 127, 131, 134, 136, 137, 138, 139, 142, 149
Offset: 1
Keywords
Examples
A179016(3) = 4 is the first case where the infinite trunk has continued to the smaller of two branches of the predecessor node. (In this case the predecessor node is A179016(2)=3, for which hold both 3+A000120(4)=3+1=4 (the smaller branch) and 3+A000120(5)=3+2=5 (the larger branch). Thus the first term of this sequence is 3. A179016(5) = 8 is the second case where the infinite trunk has continued to the smaller of two branches of the predecessor node (In this case the predecessor node is A179016(4)=7, for which hold both 7+A000120(8)=7+1=8 (the smaller branch) and 7+A000120(9)=7+2=9 (the larger branch). Thus the second term of this sequence is 5.
Links
- Antti Karttunen, Table of n, a(n) for n = 1..10000
Formula
a(n) = A218772(n)+1.
Extensions
Description changed because of the changed starting offset of A179016. - Antti Karttunen, Nov 05 2012
Comments