A221650 Tetrahedron P(n,j,k) = T(j,k)*p(n-j), where T(j,k) = 1 if k divides j otherwise 0.
1, 1, 1, 1, 2, 1, 1, 1, 0, 1, 3, 2, 2, 1, 0, 1, 1, 1, 0, 1, 5, 3, 3, 2, 0, 2, 1, 1, 0, 1, 1, 0, 0, 0, 1, 7, 5, 5, 3, 0, 3, 2, 2, 0, 2, 1, 0, 0, 0, 1, 1, 1, 1, 0, 0, 1, 11, 7, 7, 5, 0, 5, 3, 3, 0, 3, 2, 0, 0, 0, 2, 1, 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 1
Offset: 1
Examples
First six slices of tetrahedron are --------------------------------------------------- n j k: 1 2 3 4 5 6 A221530 A006128 --------------------------------------------------- 1 1 1, 1 1 ................................................... 2 1 1, 1 2 2 1, 1, 2 3 ................................................... 3 1 2, 2 3 2 1, 1, 2 3 3 1, 0, 1, 2 6 ................................................... 4 1 3, 3 4 2 2, 2, 4 4 3 1, 0, 1, 2 4 4 1, 1, 0, 1, 3 12 ................................................... 5 1 5, 5 5 2 3, 3, 6 5 3 2, 0, 2, 4 5 4 1, 1, 0, 1, 3 5 5 1, 0, 0, 0, 1, 2 20 ................................................... 6 1 7, 7 6 2 5, 5, 10 6 3 3, 0, 3, 6 6 4 2, 2, 0, 2, 6 6 5 1, 0, 0, 0, 1, 2 6 6 1, 1, 1, 0, 0, 1 4 35 ...................................................
Links
- Paolo Xausa, Table of n, a(n) for n = 1..11480 (rows n = 1..40 of the tetrahedron, flattened)
Programs
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Mathematica
A221650row[n_]:=Flatten[Table[If[Divisible[j,k],PartitionsP[n-j],0],{j,n},{k,j}]];Array[A221650row,10] (* Paolo Xausa, Sep 26 2023 *)
Comments