A222212 In the number n, replace all (decimal) digits '0' with '3' and vice versa.
3, 1, 2, 0, 4, 5, 6, 7, 8, 9, 13, 11, 12, 10, 14, 15, 16, 17, 18, 19, 23, 21, 22, 20, 24, 25, 26, 27, 28, 29, 3, 1, 2, 0, 4, 5, 6, 7, 8, 9, 43, 41, 42, 40, 44, 45, 46, 47, 48, 49, 53, 51, 52, 50, 54, 55, 56, 57, 58, 59, 63, 61, 62, 60, 64, 65, 66, 67, 68, 69, 73, 71, 72, 70, 74, 75
Offset: 0
Links
- Vincenzo Librandi, Table of n, a(n) for n = 0..1000
Programs
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Mathematica
a[n_]:= IntegerDigits[n]/.{0->3, 3->0} // FromDigits; Table[a[n], {n, 0, 80}] (* Vincenzo Librandi, Jul 29 2013 *)
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PARI
A222212(n,d=[3,1,2,0,4,5,6,7,8,9])=sum(i=1,#n=digits(n),d[n[i]+1]*10^(#n-i))+!n*d[1] \\ N.B.: PARI's digits() function returns [] for 0.
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PARI
a(n)=if(n, fromdigits(apply(d->if(d>3,d,[3,1,2,0][d+1]), digits(n))), 3) \\ Charles R Greathouse IV, Sep 27 2015
Comments