cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A226979 Number of ways to cut an n X n square into squares with integer sides, reduced for symmetry, where the orbits under the symmetry group of the square, D4, have 2 elements.

Original entry on oeis.org

0, 0, 0, 2, 2, 24, 36, 344, 504, 7657, 11978, 289829
Offset: 1

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Keywords

Examples

			For n=5, there are 2 dissections where the orbits under the symmetry group of the square, D4, have 2 elements.
For n=4, the 2 dissections can be seen in A240120 and A240121.
		

Crossrefs

Formula

A226978(n) + A226979(n) + A226980(n) + A226981(n) = A224239(n).
1*A226978(n) + 2*A226979(n) + 4*A226980(n) + 8*A226981(n) = A045846(n).
A226979(n) = A240120(n) + A240121(n) + A240122(n).

Extensions

a(8)-a(12) from Ed Wynn, Apr 01 2014

A226980 Number of ways to cut an n X n square into squares with integer sides, reduced for symmetry, where the orbits under the symmetry group of the square, D4, have 4 elements.

Original entry on oeis.org

0, 0, 1, 6, 26, 264, 1157, 23460, 153485, 6748424, 70521609, 6791578258
Offset: 1

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Author

Keywords

Examples

			For n=5, there are 26 dissections where the orbits under the symmetry group of the square, D4, have 4 elements.
The 6 dissections for n=4 can be seen in A240123 and A240125.
		

Crossrefs

Formula

A226978(n) + A226979(n) + A226980(n) + A226981(n) = A224239(n).
1*A226978(n) + 2*A226979(n) + 4*A226980(n) + 8*A226981(n) = A045846(n).
A226980(n) = A240123(n) + A240124(n) + A240125(n).

Extensions

a(8)-a(12) from Ed Wynn, Apr 01 2014

A227004 Irregular triangle read by rows: T(n,k) is the number of inequivalent tilings by squares of an n X n square lattice that contain k nodes unconnected to any of their neighbors.

Original entry on oeis.org

1, 1, 1, 1, 1, 0, 0, 1, 1, 3, 4, 2, 2, 0, 0, 0, 0, 1, 1, 3, 13, 20, 17, 6, 10, 5, 0, 1, 0, 0, 0, 0, 0, 0, 1, 1, 6, 37, 138, 280, 300, 255, 218, 98, 43, 55, 28, 20, 11, 1, 0, 2, 0, 0, 0, 0, 0, 0, 0, 0, 1
Offset: 1

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Comments

The n-th row contains (n-1)^2 + 1 elements.
The irregular triangle is shown below.
\ k 0 1 2 3 4 5 6 7 8 9 ...
n
1 1
2 1 1
3 1 1 0 0 1
4 1 3 4 2 2 0 0 0 0 1
5 1 3 13 20 17 6 10 5 0 1 ...
6 1 6 37 138 280 300 255 218 98 43 ...
7 1 6 75 505 2160 5410 8508 9179 8805 7917 ...

Examples

			For n = 4, there are 3 inequivalent tilings that contain 1 isolated node, so T(4,1) = 3.
A 2 X 2 square contains 1 isolated node.
Consider that each tiling is composed of ones and zeros where a one represents a node with one or more links to its neighbors and a zero represents a node with no links to its neighbors.  Then the 3 tilings are:
1 1 1 1 1    1 1 1 1 1    1 1 1 1 1
1 0 1 1 1    1 1 0 1 1    1 1 1 1 1
1 1 1 1 1    1 1 1 1 1    1 1 0 1 1
1 1 1 1 1    1 1 1 1 1    1 1 1 1 1
1 1 1 1 1    1 1 1 1 1    1 1 1 1 1
		

Crossrefs

Cf. A224239.

Formula

Sum_{k=0..(n-1)^2} T(n,k) = A224239(n).

A226978 Number of ways to cut an n X n square into squares with integer sides, reduced for symmetry, where the orbits under the symmetry group of the square, D4, have 1 element.

Original entry on oeis.org

1, 2, 2, 4, 4, 12, 8, 44, 32, 228, 148, 1632, 912, 16004, 8420, 213680, 101508, 3933380, 1691008, 98949060, 38742844, 3413919788, 1213540776, 161410887252, 52106993880
Offset: 1

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Comments

From Walter Trump, Dec 15 2022: (Start)
a(n) is the number of fully symmetric dissections of an n X n square into squares with integer sides.
Conjecture: For n>3 the number of dissections is a multiple of 4. (End)

Examples

			For n=5, there are 4 dissections where the orbits under the symmetry group of the square, D4, have 1 element.
For n=4, 3 dissections divide the square into uniform subsquares (of sizes 1, 2 and 4 respectively), and this is the 4th:
---------
| | | | |
---------
| |   | |
---   ---
| |   | |
---------
| | | | |
---------
		

Crossrefs

Formula

a(n) + A226979(n) + A226980(n) + A226981(n) = A224239(n).
1*a(n) + 2*A226979(n) + 4*A226980(n) + 8*A226981(n) = A045846(n).

Extensions

a(8)-a(12) from Ed Wynn, Apr 02 2014
a(13)-a(25) from Walter Trump, Dec 15 2022
Showing 1-4 of 4 results.