A227861 Sum i + j for integers 2^i*3^j (A033845).
2, 3, 3, 4, 4, 5, 4, 5, 6, 5, 6, 5, 7, 6, 7, 6, 8, 7, 6, 8, 7, 9, 8, 7, 9, 8, 7, 10, 9, 8, 10, 9, 8, 11, 10, 9, 8, 11, 10, 9, 12, 11, 10, 9, 12, 11, 10, 13, 9, 12, 11, 10, 13, 12, 11, 14, 10, 13, 12, 11, 14, 10, 13, 12, 15, 11, 14, 13, 12, 15, 11, 14, 13, 16, 12, 15, 11, 14, 13, 16, 12, 15, 14, 17, 13, 16, 12, 15, 14, 17, 13, 16, 12, 15, 18, 14, 17, 13
Offset: 1
Keywords
Examples
a(10) = 5 because A033845(10) = 108 = 2^2 + 3^3 => A191475(10) = 2, A191476(10) = 3.
Links
- Zak Seidov, Table of n, a(n) for n = 1..10000
Comments