cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A228825 Delayed continued fraction of e.

Original entry on oeis.org

2, 2, -1, -1, -1, -2, 2, -2, 1, 1, 1, 2, -2, 2, -2, 2, -1, -1, -1, -2, 2, -2, 2, -2, 2, -2, 1, 1, 1, 2, -2, 2, -2, 2, -2, 2, -2, 2, -1, -1, -1, -2, 2, -2, 2, -2, 2, -2, 2, -2, 2, -2, 1, 1, 1, 2, -2, 2, -2, 2, -2, 2, -2, 2, -2, 2, -2, 2, -1, -1, -1, -2, 2, -2
Offset: 0

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Author

Clark Kimberling, Sep 04 2013

Keywords

Comments

An algorithm for the (usual) continued fraction of r > 0 follows: x(0) = r, a(n) = floor(x(n)), x(n+1) = 1/(x(n) - a(n)).
The accelerated continued fraction uses "round" instead of "floor" (cf. A133593, A133570, A228667), where round(x) is the integer nearest x.
The delayed continued fraction (DCF) uses "second nearest integer", so that all the terms are in {-2, -1, 1, 2}. If s/t and u/v are consecutive convergents of a DCF, then |s*x-u*t| = 1.
Regarding DCF(e), after the initial (2,2), the strings (-1,-1,-1) and (1,1,1) alternate with odd-length strings of the forms (-2,2,...,-2) and (2,-2,...,2). The string lengths form the sequence 2,3,3,3,5,3,7,3,9,3,11,3,13,3,...
Comparison of convergence rates is indicated by the following approximate values of x-e, where x is the 20th convergent: for delayed CF, x-e = 5.4x10^-7; for classical CF, x-e = 6.1x10^-16; for accelerated CF, x-e = -6.6x10^-27. The convergents for accelerated CF are a proper subset of those for classical CF, which are a proper subset of those for delayed CF (which are sampled in Example).

Examples

			Convergents: 2, 5/2, 3, 8/3, 11/4, 30/11, 49/18, 68/25, 19/7, 87/32, 106/39, 299/110, 492/181,...
		

Crossrefs

Programs

  • Mathematica
    $MaxExtraPrecision = Infinity; x[0] = E; s[x_] := s[x] = If[FractionalPart[x] < 1/2, Ceiling[x], Floor[x]]; a[n_] := a[n] = s[Abs[x[n]]]*Sign[x[n]]; x[n_] := 1/(x[n - 1] - a[n - 1]); t = Table[a[n], {n, 0, 100}]

A228668 Array: row n consists of n-th nonsquare f(n) followed by L(CF(sqrt(f(n)))) followed by L(ACF(sqrt(f(n)))), where L indicates the length of the repeating string; CF indicates continued fraction, and ACF indicates accelerated continued fraction.

Original entry on oeis.org

2, 1, 1, 3, 2, 2, 5, 1, 1, 6, 2, 2, 7, 2, 4, 8, 2, 2, 10, 1, 1, 11, 2, 2, 12, 2, 2, 13, 3, 5, 14, 2, 4, 15, 2, 2, 17, 1, 1, 18, 2, 2, 19, 4, 6, 20, 2, 2, 21, 4, 6, 22, 4, 6, 23, 2, 4, 24, 2, 2, 26, 1, 1, 27, 2, 2, 28, 4, 4, 29, 8, 5, 30, 2, 2, 31, 6, 8, 32
Offset: 1

Views

Author

Clark Kimberling, Aug 29 2013

Keywords

Comments

See A228667 for the definition of accelerated continued fraction.

Examples

			The initial 2,1,1 means that both the ACF and CF of sqrt(2) have repeating strings of length 1; the next 3,2,2 means that the ACF and CF of sqrt(3) have repeating strings of length 2 and 2.  In the table below, Mathematica notation is used for repeating continued fractions; x(n) approximates sqrt(n)-ACF(sqrt(n)) and y(n) approximates sqrt(n)-CF(sqrt(n)).
n . ACF(sqrt(n)) . x(n) ........... CF(sqrt(n)) ... y(n)
2 . {1,{2}} ..... -0.32 ........... {1,{2}} ....... -0.32
3 . {2,{-4,4}} .. -1.3 x 10^(-11) . {1,{1,2}} ..... -7 x 10^(-6)
7 . {3,{-3,6}} .. -5.0 x 10^(-12) . {2,{1,1,1,4}} . -5 x 10^(-6)
		

Crossrefs

Programs

  • Mathematica
    $MaxExtraPrecision = Infinity; period[seq_] := (If[Last[#1] == {} || Length[#1] == Length[seq] - 1, 0, Length[#1]] &)[NestWhileList[Rest, Rest[seq], #1 != Take[seq, Length[#1]] &, 1]]; periodicityReport[seq_] := ({Take[seq, Length[seq] - Length[#1]], period[#1], Take[#1, period[#1]]} &)[Take[seq, -Length[NestWhile[Rest[#1] &, seq, period[#1] == 0 &, 1, Length[seq]]]]]
    (*output format {initial seqment,period length,period}*)
    (*error messages occur if the sequence not found to be periodic.*)
    aCF[rational_] := Module[{steps = {}, stop = False, i = 0, x = Numerator[rational], y = Denominator[rational], w, u, v, f, c},(*Step 1*)w = Mod[x, y]; Which[w == 0, c[i] = x/y; stop = True; AppendTo[steps, "A"], 0 < w <= y/2, c[i] = Floor[x/y]; {u, v, f} = {y, w, 1}; AppendTo[steps, "B"], w > y/2, c[i] = 1 + Floor[x/y]; {u, v, f} = {y, y - w, -1};    AppendTo[steps, "C"]];  i++; (*Step 2*)While[stop =!= True, w = Mod[u, v]; Which[f == 1 && w == 0, c[i] = u/v; stop = True; AppendTo[steps, "0.1"], f == -1 && w == 0, c[i] = -u/v; stop = True; AppendTo[steps, "0.2"], f == 1 && w <= v/2, c[i] = Floor[u/v]; {u, v, f} = {v, w, 1}; AppendTo[steps, "1"], f == 1 && w > v/2, c[i] = 1 + Floor[u/v]; {u, v, f} = {v, v - w, -1}; AppendTo[steps, "2"], f == -1 && w <= v/2, c[i] = -Floor[u/v]; {u, v, f} = {v, w, -1}; AppendTo[steps, "3"], f == -1 && w > v/2, c[i] = -1 - Floor[u/v]; {u, v, f} = {v, v - w, -f}; AppendTo[steps, "4"]]; i++]; (*Display results*) {FromContinuedFraction[#], {"Steps", steps}, {"ACF", #}, {"CF", ContinuedFraction[x/y]}} &[Map[c, Range[i] - 1]]]
    m = Map[{#, Map[periodicityReport[#][[2]] &, {Drop[#[[1]][[2]], -3],    Drop[#[[2]][[2]], -3]} &[aCF[Rationalize[Sqrt[#], 10^-80]][[{3, 4}]]]]} &, Select[Range[200], ! IntegerQ[Sqrt[#]] &]]
    Flatten[m] (* Peter J. C. Moses, Aug 28 2013 *)
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