cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A211168 Exponent of alternating group An.

Original entry on oeis.org

1, 1, 3, 6, 30, 60, 420, 420, 1260, 2520, 27720, 27720, 360360, 360360, 360360, 360360, 6126120, 12252240, 232792560, 232792560, 232792560, 232792560, 5354228880, 5354228880, 26771144400, 26771144400, 80313433200, 80313433200, 2329089562800, 2329089562800
Offset: 1

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Author

Alexander Gruber, Jan 31 2013

Keywords

Comments

a(n) is the smallest natural number m such that g^m = 1 for any g in An.
If m <= n, a m-cycle occurs in some permutation in An if and only if m is odd or m <= n - 2. The exponent is the LCM of the m's satisfying these conditions, leading to the formula below.

Examples

			For n = 7, lcm{1,...,5,7} = 420.
		

Crossrefs

Even entries given by the sequence A076100, or the odd entries in the sequence A003418.
The records of this sequence are a subsequence of A002809 and A126098.

Programs

  • Magma
    for n in [1..40] do
    Exponent(AlternatingGroup(n));
    end for;
    
  • Magma
    for n in [1..40] do
    if n mod 2 eq 0 then
    L := [1..n-1];
    else
    L := Append([1..n-2],n);
    end if;
    LCM(L);
    end for;
    
  • Mathematica
    Table[If[Mod[n, 2] == 0, LCM @@ Range[n - 1],
      LCM @@ Join[Range[n - 2], {n}]], {n, 1, 100}] (* or *)
    a[1] = 1; a[2] = 1; a[3] = 3; a[n_] := a[n] =
      If[Mod[n, 2] == 0, LCM[a[n - 1], n - 2], LCM[a[n - 2], n - 3, n]]; Table[a[n], {n, 1, 40}]
  • PARI
    a(n)=lcm(if(n%2,concat([2..n-2],n),[2..n-1])) \\ Charles R Greathouse IV, Mar 02 2014

Formula

Explicit:
a(n) = lcm{1, ..., n-1} if n is even.
= lcm{1, ..., n-2, n} if n is odd.
Recursive:
Let a(1) = a(2) = 1 and a(3) = 3. Then
a(n) = lcm{a(n-1), n-2} if n is even.
= lcm{a(n-2), n-3, n} if n is odd.
a(n) = A003418(n)/(1 + [n in A228693]) for n > 1. - Charlie Neder, Apr 25 2019

A343949 Shortest distance from curve start to end along the segments of dragon curve expansion level n, and which is the diameter of the curve as a graph.

Original entry on oeis.org

1, 2, 4, 8, 12, 18, 26, 36, 52, 70, 102, 136, 200, 266, 394, 524, 780, 1038, 1550, 2064, 3088, 4114, 6162, 8212, 12308, 16406, 24598, 32792, 49176, 65562, 98330, 131100, 196636, 262174, 393246, 524320, 786464, 1048610, 1572898, 2097188, 3145764, 4194342, 6291494
Offset: 0

Views

Author

Kevin Ryde, May 05 2021

Keywords

Comments

Expansion level n is the first 2^n segments of the curve, and can be taken as a graph with visited points as vertices and segments as edges.

Examples

			Curve n=4:
     *--*  *--*
     |  |  |  |        Start S to end E along segments.
     *--*--*  *--*     Distance a(4) = 12,
        |        |     which is also graph diameter.
  E  *--*     S--*
  |  |
  *--*
		

Crossrefs

Cf. A332383, A332384 (curve coordinates).

Programs

  • PARI
    a(n) = if(n==0,1, my(t=n%2); (3+t)<<(n>>1) + n-4 + t);

Formula

a(0) = 1.
a(2*n) = 3*2^n + 2*n - 4 = 2*A275970(n-1), for n>=1.
a(2*n+1) = 4*2^n + 2*n - 2 = 2*A083706(n).
a(n+1) - a(n) = 2*A228693(n), for n>=1.
a(n) = a(n-1) + 3*a(n-2) - 3*a(n-3) - 2*a(n-4) + 2*a(n-5) for n >= 6.
G.f.: (1 + x - x^2 + x^3 - 4*x^5) / ((1+x) * (1-x)^2 * (1-2*x^2)).
G.f.: 2 - (1/2)/(1+x) - (9/2)/(1-x) + 1/(1-x)^2 + (3 + 4*x)/(1 - 2*x^2).
Showing 1-2 of 2 results.