A228919 Numbers n such that 1^(n+1) + 2^(n+1) + ... + n^(n+1) == 0 (mod n).
1, 4, 5, 7, 8, 11, 12, 13, 16, 17, 19, 20, 23, 24, 25, 28, 29, 31, 32, 36, 37, 40, 41, 43, 44, 47, 48, 49, 52, 53, 56, 59, 60, 61, 64, 65, 67, 68, 71, 72, 73, 76, 79, 80, 83, 84, 85, 88, 89, 91, 92, 96, 97, 100, 101, 103, 104, 107, 108, 109, 112, 113, 116
Offset: 1
Keywords
Links
- Charles R Greathouse IV, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
f[n_] := Mod[Sum[PowerMod[i, n + 1, n], {i, 1, n}], n]; Select[Range[1000], f[#] == 0 &]
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PARI
is(n)=my(m=n+1);sum(k=1,n,Mod(k,n)^m)==0 \\ Charles R Greathouse IV, Nov 20 2013