cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A231176 Let A={1,3,4,7,8,10,13,15,...} be the sequence of numbers k>=1 such that k+2 is evil (A001969), let B be the complement of A. The sequence lists numbers for which the number of A-divisors equals the number of B-divisors.

Original entry on oeis.org

1, 4, 25, 36, 100, 121, 289, 361, 529, 625, 841, 1156, 1764, 2116, 2209, 2500, 2809, 3249, 3364, 3481, 4489, 5041, 5929, 6241, 7225, 7396, 7921, 10201, 11236, 11449, 12769, 12996, 15625, 17161, 20164, 21025, 22201, 27556, 28900, 30276, 30625, 31329, 31684
Offset: 1

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Author

Vladimir Shevelev, Nov 05 2013

Keywords

Comments

An analog of A227891. All terms are perfect squares.

Examples

			n=100 has 8 proper divisors {1,2,4,5,10,20,25,50} from which 4 from A {1,4,10,25} and 4 from B {2,5,20,50}. So 100 is in the sequence.
		

Crossrefs

Programs

  • Mathematica
    odiousQ[n_]:=OddQ[DigitCount[n,2][[1]]];
    Select[Range[100],0==Length[#]-2Length[Select[#,odiousQ[#+2]&]]&[Most[Divisors[#^2]]]&]^2 (* Peter J. C. Moses, Nov 08 2013 *)

Extensions

More terms from Peter J. C. Moses, Nov 05 2013

A231177 Let A = {1,4,5,8,10,11,13,...} be the sequence of numbers k>=1 such that k+3 is odious (A000069), and let B be the complement of A. The sequence lists the numbers for which the number of A-divisors equals the number of B-divisors.

Original entry on oeis.org

1, 4, 9, 49, 196, 289, 961, 1156, 1369, 1849, 3249, 3844, 5476, 6889, 7921, 8281, 10609, 12769, 12996, 14161, 15129, 16129, 17689, 19321, 22801, 24649, 25281, 26569, 27889, 28561, 29584, 31329, 31684, 32761, 39601, 42436, 44944, 45369, 49729, 51076, 52441
Offset: 1

Views

Author

Keywords

Comments

All terms are perfect squares.

Examples

			n=196 has 8 proper divisors {1,2,4,7,14,28,49,98} from which 4 from A {1,4,28,49} and 4 from B {2,7,14,98}. So 196 is in the sequence.
		

Crossrefs

Programs

  • Mathematica
    odiousQ[n_]:=OddQ[DigitCount[n,2][[1]]];
    Select[Range[200],0==Length[#]-2Length[Select[#,odiousQ[#+3]&]]&[Most[Divisors[#^2]]]&]^2 (* Peter J. C. Moses, Nov 08 2013 *)

A231178 Let A={1,2,5,6,8,11,13,...} be the sequence of numbers k>=1 such that k+4 is evil (A001969), and let B be the complement of A. The sequence lists numbers for which the number of A-divisors equals number of B-divisors.

Original entry on oeis.org

1, 9, 49, 289, 324, 676, 961, 1369, 1849, 3249, 4356, 6084, 6889, 7921, 8281, 8836, 10609, 11236, 12769, 14161, 14884, 15129, 16129, 17689, 19321, 21316, 22500, 22801, 24649, 25281, 26569, 27889, 28561, 30276, 31329, 32761, 39601, 44944, 45369, 45796, 47524
Offset: 1

Views

Author

Keywords

Comments

All terms are perfect squares.

Examples

			324 has 14 proper divisors {1,2,3,4,6,9,12,18,27,36,54,81,108,162} from which 7 from A {1,2,6,36,54,81,162} and 7 from B {3,4,9,12,18,27,108}. So 324 is in the sequence.
		

Crossrefs

Programs

  • Mathematica
    odiousQ[n_]:=OddQ[DigitCount[n,2][[1]]];
    Select[Range[200],0==Length[#]-2Length[Select[#,odiousQ[#+4]&]]&[Most[Divisors[#^2]]]&]^2 (* Peter J. C. Moses, Nov 08 2013 *)

A231180 Let A={2,3,6,8,9,11,14,...} be the sequence of numbers k>=1 such that k+5 is odious (A000069). Let B be the complement of A. The sequence lists numbers for which the number of A-divisors equals the number of B-divisors.

Original entry on oeis.org

1, 4, 9, 16, 36, 121, 144, 289, 441, 484, 529, 1156, 1369, 1600, 1764, 2025, 2116, 2209, 3249, 3481, 4624, 5041, 5476, 6241, 6889, 7056, 7569, 7921, 8100, 8464, 8649, 8836, 11449, 12321, 12769, 12996, 13924, 14641, 15129, 16641, 20164, 24336, 24649, 24964
Offset: 1

Views

Author

Keywords

Comments

All terms are perfect squares.

Examples

			n=16 has 4 proper divisors {1,2,4,8} from which 2 from A {2,8} and 2 from B {1,4}. So 16 is in the sequence.
		

Crossrefs

Programs

  • Mathematica
    odiousQ[n_]:=OddQ[DigitCount[n,2][[1]]];
    Select[Range[200],0==Length[#]-2Length[Select[#,odiousQ[#+5]&]]&[Most[Divisors[#^2]]]&]^2 (* Peter J. C. Moses, Nov 08 2013 *)
Showing 1-4 of 4 results.