A232740 a(n) = Number of terms of A232739 which occur between each consecutive terms of A005228, in range A005228(n)..A005228(n+1).

1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 1, 2, 1, 1, 1, 1, 2, 1, 1, 1, 1, 2, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1

Offset: 1

Author

Antti Karttunen, Dec 04 2013

Keywords

• nonn

Comments

Do any other values appear than 1 and 2? The 2's seem to be getting rarer, as zeros correspondingly get rarer in A232750. This has some implications about how the ratio A005228(n)/A232739(n) will develop. Please see also the comments and graph-drawing link in A232739.

Examples

			The two sequences begin as:
A005228: 1, 3,    7, 12,      18,   26,     35,  45,   56,      69,   83, ...
A232739:  2,  4,6,  9,  13,17,   22,   28,34,  41,  49,   58,67,   77,   ...
Grouping together the terms of A232739 that occur between two successive terms of A232739, we get {2}, {4,6}, {9}, {13,17}, {22}, {28,34}, {41}, {49}, {58,67}, {77}, ... and counting how many terms are in each such group, we get 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, ..., the first terms of this sequence.
		

Links

• Antti Karttunen, Table of n, a(n) for n = 1..2009
• Index entries for Hofstadter-type sequences

Crossrefs

Cf. A005228, A232739, A232750, A232753.

Programs

Scheme

(define (A232740 n) (- (A232753 (A005228 (+ n 1))) (A232753 (A005228 n))))

Formula

a(n) = A232753(A005228(n+1)) - A232753(A005228(n)).