cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A226080 Denominators in the Fibonacci (or rabbit) ordering of the positive rational numbers.

Original entry on oeis.org

1, 1, 1, 2, 1, 3, 2, 1, 4, 3, 2, 3, 1, 5, 4, 3, 4, 2, 5, 3, 1, 6, 5, 4, 5, 3, 7, 4, 2, 7, 5, 3, 5, 1, 7, 6, 5, 6, 4, 9, 5, 3, 10, 7, 4, 7, 2, 9, 7, 5, 7, 3, 8, 5, 1, 8, 7, 6, 7, 5, 11, 6, 4, 13, 9, 5, 9, 3, 13, 10, 7, 10, 4, 11, 7, 2, 11, 9, 7, 9, 5, 12, 7
Offset: 1

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Author

Clark Kimberling, May 25 2013

Keywords

Comments

Let S be the set of numbers defined by these rules: 1 is in S, and if x is in S, then x+1 and 1/x are in S. Then S is the set of positive rational numbers, which arise in generations as follows: g(1) = (1/1), g(2) = (1+1) = (2), g(3) = (2+1, 1/2) = (3/1, 1/2), g(4) = (4/1, 1/3, 3/2), ... . Once g(n-1) = (g(1), ..., g(z)) is defined, g(n) is formed from the vector (g(1) + 1, 1/g(1), g(2) + 1, 1/g(2), ..., g(z) + 1, 1/g(z)) by deleting all elements that are in a previous generation. A226080 is the sequence of denominators formed by concatenating the generations g(1), g(2), g(3), ... . It is easy to prove the following:
(1) Every positive rational is in S.
(2) The number of terms in g(n) is the n-th Fibonacci number, F(n) = A000045(n).
(3) For n > 2, g(n) consists of F(n-2) numbers < 1 and F(n-1) numbers > 1, hence the name "rabbit ordering" since the n-th generation has F(n-2) reproducing pairs and F(n-1) non-reproducing pairs, as in the classical rabbit-reproduction introduction to Fibonacci numbers.
(4) The positions of integers in S are the Fibonacci numbers.
(5) The positions of 1/2, 3/2, 5/2, ..., are Lucas numbers (A000032).
(6) Continuing from (4) and (5), suppose that n > 0 and 0 < r < n, where gcd(n,r) = 1. The positions in A226080 of the numbers congruent to r mod n comprise a row of the Wythoff array, W = A035513. The correspondence is sampled here:
row 1 of W: positions of n+1 for n>=0,
row 2 of W: positions of n+1/2,
row 3 of W: positions of n+1/3,
row 4 of W: positions of n+1/4,
row 5 of W: positions of n+2/3,
row 6 of W: positions of n+1/5,
row 7 of W: positions of n+3/4.
(7) If the numbers <=1 in S are replaced by 1 and those >1 by 0, the resulting sequence is the infinite Fibonacci word A003849 (except for the 0-offset first term).
(8) The numbers <=1 in S occupy positions -1 + A001950, where A001950 is the upper Wythoff sequence; those > 1 occupy positions given by -1 + A000201, where A000201 is the lower Wythoff sequence.
(9) The rules (1 is in S, and if x is in S, then 1/x and 1/(x+1) are in S) also generate all the positive rationals.
A variant which extends this idea to an ordering of all rationals is described in A226130. - M. F. Hasler, Jun 03 2013
The updown and downup zigzag limits are (-1 + sqrt(5))/2 and (1 + sqrt(5))/2; see A020651. - Clark Kimberling, Nov 10 2013
From Clark Kimberling, Jun 19 2014: (Start)
Following is a guide to related trees and sequences; for example, the tree A226080 is represented by (1, x+1, 1/x), meaning that 1 is in S, and if x is in S, then x+1 and 1/x are in S (except for x = 0).
All the positive integers:
A243571, A243572, A232559 (1, x+1, 2x)
A232561, A242365, A243572 (1, x+1, 3x)
A243573 (1, x+1, 4x)
All the integers:
A243610 (1, 2x, 1-x)
All the positive rationals:
A226080, A226081, A242359, A242360 (1, x+1, 1/x)
A243848, A243849, A243850 (1, x+1, 2/x)
A243851, A243852, A243853 (1, x+1, 3/x)
A243854, A243855, A243856 (1, x+1, 4/x)
A243574, A242308 (1, 1/x, 1/(x+1))
A241837, A243575 ({1,2,3}, x+4, 12/x)
A242361, A242363 (1, 1 + 1/x, 1/x)
A243613, A243614 (0, x+1, x/(x+1))
All the rationals:
A243611, A243612 (0, x+1, -1/(x+1))
A226130, A226131 (1, x+1, -1/x)
A243712, A243713 ({1,2,3}, x+1, 1/(x+1))
A243730, A243731 ({1,2,3,4}, x+1, 1/(x+1))
A243732, A243733 ({1,2,3,4,5}, x+1, 1/(x+1))
A243925, A243926, A243927 (1, x+1, -2/x)
A243928, A243929, A243930 (1, x+1, -3/x)
All the Gaussian integers:
A243924 (1, x+1, i*x)
All the Gaussian rational numbers:
A233694, A233695, A233696 (1, x+1, i*x, 1/x).
(End)

Examples

			The denominators are read from the rationals listed in "rabbit order":
1/1, 2/1, 3/1, 1/2, 4/1, 1/3, 3/2, 5/1, 1/4, 4/3, 5/2, 2/3, 6/1, ...
		

Crossrefs

Cf. A000045, A035513, A226081 (numerators), A226130, A226247, A020651.

Programs

  • Mathematica
    z = 10; g[1] = {1}; g[2] = {2}; g[3] = {3, 1/2};
    j[3] = Join[g[1], g[2], g[3]]; j[n_] := Join[j[n - 1], g[n]];
    d[s_List, t_List] := Part[s, Sort[Flatten[Map[Position[s, #] &, Complement[s, t]]]]]; j[3] = Join[g[1], g[2], g[3]]; n = 3; While[n <= z, n++; g[n] = d[Riffle[g[n - 1] + 1, 1/g[n - 1]], g[n - 2]]];
    Table[g[n], {n, 1, z}]; j[z] (* rabbit-ordered rationals *)
    Denominator[j[z]]  (* A226080 *)
    Numerator[j[z]]    (* A226081 *)
    Flatten[NestList[(# /. x_ /; x > 1 -> Sequence[x, 1/x - 1]) + 1 &, {1}, 9]] (* rabbit-ordered rationals, Danny Marmer, Dec 07 2014 *)
  • PARI
    A226080_vec(N=100)={my(T=[1],S=T,A=T); while(N>#A=concat(A, apply(denominator, T=select(t->!setsearch(S,t), concat(apply(t->[t+1,1/t],T))))), S=setunion(S,Set(T)));A} \\ M. F. Hasler, Nov 30 2018
    
  • PARI
    (A226080(n)=denominator(RabbitOrderedRational(n))); ROR=List(1); RabbitOrderedRational(n)={if(n>#ROR, local(S=Set(ROR), i=#ROR*2\/(sqrt(5)+1), a(t)=setsearch(S,t)||S=setunion(S,[listput(ROR,t)])); until( type(ROR[i+=1])=="t_INT" && n<=#ROR, a(ROR[i]+1); a(1/ROR[i])));ROR[n]} \\ M. F. Hasler, Nov 30 2018

A233696 Positions of integers in the sequence (or tree) S generated in order by these rules: 0 is in S; if x is in S then x + 1 is in S; if nonzero x is in S then 1/x is in S; if x is in S, then i*x is in S; where duplicates are deleted as they occur.

Original entry on oeis.org

1, 2, 3, 5, 10, 11, 18, 23, 30, 49, 56, 102, 109, 212, 219, 443, 450, 926, 933, 1939, 1946, 4064, 4071, 8509, 8516, 17816, 17823, 37303, 37310, 78105, 78112, 163544, 163551
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2013

Keywords

Comments

It can be proved using the division algorithm for Gaussian integers that S is the set of Gaussian rational numbers: (b + c*i)/d, where b,c,d are integers and d is not 0.

Examples

			The first 16 numbers generated are as follows:  0, 1, 2, i, 3, 1/2, 2 i, 1 + i, -i, -1, 4, 1/3, 3 i, 3/2, i/2, 1 + 2 i.  Positions of integers 0, 1, 2, 3, -1, 4,... are 1,2,3,5,10,11,....
		

Crossrefs

Programs

  • Mathematica
    Off[Power::infy]; x = {0}; Do[x = DeleteDuplicates[Flatten[Transpose[{x, x + 1, 1/x, I*x} /. ComplexInfinity -> 0]]], {18}]; On[Power::infy]; t1 = Flatten[Position[x, _?(IntegerQ[#] && NonNegative[#] &)]]    (*A233694*)
    t2 = Flatten[Position[x, _?(IntegerQ[#] && Negative[#] &)]]  (*A233695*)
    t = Union[t1, t2]  (*A233696*)
    (* Peter J. C. Moses, Dec 21 2013 *)

Extensions

Definition and example corrected. - R. J. Mathar, May 06 2017

A233695 a(n) gives the position of -n in the sequence (or tree) S generated in order by these rules: 0 is in S; if x is in S then x + 1 is in S; if nonzero x is in S then 1/x is in S; if x is in S, then i*x is in S; where duplicates are deleted as they occur.

Original entry on oeis.org

10, 18, 30, 56, 109, 219, 450, 933, 1946, 4071, 8516, 17823, 37310, 78112, 163551, 342461, 717083, 1501509, 3144031, 6583341, 13784976
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2013

Keywords

Comments

It can be proved using the division algorithm for Gaussian integers that S is the set of Gaussian rational numbers: (b + c*i)/d, where b,c,d are integers and d is not 0.
Empirically, it appears that a(n) = A233694(n+2) + 7 for n > 2. It seems clear that positive integers appear for the first time at the start of a new level of the tree. If this is always the case, then the row starting with n will be followed by a row starting n+1, 1/n, ni, followed by a row starting n+2, 1/(n+1), (n+1)i, 1+1/n, n+1, i/(n+1), 1+ni, -i/n, -n. It may be possible to show that of these 9 values, only n+1 has ever appeared before. If so, then -n will always appear exactly 7 places after n + 2 in the sequence. - Jack W Grahl, Aug 10 2018

Examples

			The first 16 numbers generated are as follows:  0, 1, 2, i, 3, 1/2, 2 i, 1 + i, -i, -1, 4, 1/3, 3 i, 3/2, i/2, 1 + 2 i. -1 appears in the 10th place, so a(1) = 10.
		

Crossrefs

Programs

  • Mathematica
    Off[Power::infy]; x = {0}; Do[x = DeleteDuplicates[Flatten[Transpose[{x, x + 1, 1/x, I*x} /. ComplexInfinity -> 0]]], {18}]; On[Power::infy]; t1 = Flatten[Position[x, _?(IntegerQ[#] && NonNegative[#] &)]]   (*A233694*)
    t2 = Flatten[Position[x, _?(IntegerQ[#] && Negative[#] &)]] (* A233695 *)
    t = Union[t1, t2]  (* A233696 *)
    (* Peter J. C. Moses, Dec 21 2013 *)

Extensions

More terms by Jack W Grahl, Aug 10 2018

A243924 Irregular triangular array of taxicab norms of Gaussian integers in array G generated as at Comments.

Original entry on oeis.org

0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 3, 3, 4, 2, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 7, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 8, 6, 6, 6
Offset: 1

Views

Author

Clark Kimberling, Jun 17 2014

Keywords

Comments

An array G of Gaussian integers is generated as follows: (row 1) = (0), and for n >=2, row n consists of the numbers x+1 and then i*x, where duplicates are deleted as they occur. Every Gaussian integer occurs exactly once in G. The taxicab norm of a Gaussian integer b+c*i is the taxicab distance (also known as Manhattan distance) from 0 to b+c*i, given by |b|+|c|. The norms of numbers in row n are given here in nondecreasing order. Conjecture: the number of numbers in row n is 4n-13 for n >= 5.

Examples

			First 6 rows of G:
0
1
2 .. i
3 .. 2i .. i+1 ... -1
4 .. 3i .. 1+2i .. -2 .. i+2 .. -1+i . -i
5 .. 4i .. 1+3i .. -3 .. 2+2i . -2+i . -2i . i+3 . -1+2i . -1-i . 1-i
The corresponding taxicab norms follow:
0
1
1 2
1 2 2 3
2 2 1 3 3 3 4
3 3 2 3 2 4 2 4 4 4 5
Each row is then arranged in nondecreasing order:
0
1
1 2
1 2 2 3
1 2 2 3 3 3 4
2 2 2 3 3 3 4 4 4 4 5
		

Crossrefs

Programs

  • Mathematica
    z = 10; g[1] = {0}; f1[x_] := x + 1; f2[x_] := I*x; h[1] = g[1];
    b[n_] := b[n] = DeleteDuplicates[Union[f1[g[n - 1]], f2[g[n - 1]]]];
    h[n_] := h[n] = Union[h[n - 1], g[n - 1]];
    g[n_] := g[n] = Complement [b[n], Intersection[b[n], h[n]]]
    Table[g[n], {n, 1, z}] (* the array G *)
    v = Table[Abs[Re[g[n]]] + Abs[Im[g[n]]], {n, 1, z}]
    w = Map[Sort, v] (* A243924, rows *)
    w1 = Flatten[w]  (* A243924, sequence *)
Showing 1-4 of 4 results.