A236335 Lexicographically earliest sequence of positive integers whose graph has no three collinear points.
1, 1, 2, 2, 5, 4, 9, 3, 3, 6, 8, 5, 6, 9, 17, 4, 8, 15, 13, 24, 17, 13, 26, 32, 14, 7, 12, 29, 12, 18, 10, 10, 23, 35, 7, 16, 14, 30, 24, 23, 30, 46, 27, 20, 52, 15, 25, 40, 29, 40, 19, 38, 58, 18, 39, 42, 16, 69, 33, 25, 67, 43, 11, 51, 28, 11, 54, 73, 26, 27
Offset: 1
Keywords
Examples
Consider a(5). The previous terms are 1,1,2,2. The value of a(5) can't be 1 because points (1,1),(2,1),(5,1) (corresponding to values a(1), a(2), a(5)) are on the same line: y=1. Points (3,2),(4,2),(5,2) are on the same line y=2, so a(5) can't be 2. Points (1,1),(3,2),(5,3) are on the same line: y=x/2+1/2, so a(5) can't be 3. Points (2,1),(3,2),(5,4) are on the same line: y=x-1, so a(5) can't be 4. Thus a(5)=5.
Links
- Grant Garcia, Table of n, a(n) for n = 1..10000
- Dániel T. Nagy, Zoltán Lóránt Nagy, and Russ Woodroofe, The extensible No-Three-In-Line problem, arXiv:2209.01447 [math.CO], 2022.
Programs
-
Mathematica
b[1] = 1; b[n_] := b[n] = Min[Complement[Range[100], Select[Flatten[ Table[b[k] + (n - k) (b[j] - b[k])/(j - k), {k, n - 2}, {j, k + 1, n - 1}]], IntegerQ[#] &]]] Table[b[k], {k, 70}]
Formula
a(n) = A236266(n-1) + 1. - Alois P. Heinz, Jan 23 2014
Comments