A244060 Sum of digits of (2^n)!.
1, 2, 6, 9, 63, 108, 324, 828, 1989, 4635, 10845, 24363, 54279, 118827, 258705, 565389, 1216134, 2611359, 5584518, 11875977, 25184205, 53209728, 112069377, 235502361, 493827687, 1033041267, 2156974227, 4495662081, 9355185828, 19437382512, 40329016200
Offset: 0
Examples
If n=4, 2^4! = 16! = 20922789888000, with digit sum 63. - _N. J. A. Sloane_, Jun 18 2014
Programs
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Mathematica
f[n_] := Total[ IntegerDigits[ (2^n)!]]; Array[f, 20, 0]
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PARI
a(n) = sumdigits((2^n)!); \\ Michel Marcus, Oct 25 2021
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Python
from math import factorial def A244060(n): return sum(int(d) for d in str(factorial(2**n))) # Chai Wah Wu, Oct 26 2021
Formula
Extensions
a(26)-a(30) from Chai Wah Wu, Oct 25 2021