cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A294129 Numbers n for which exactly one length minimal language exists having exactly n nonempty words over a countably infinite alphabet such that within each prefix of a word every letter of the alphabet is at least as frequent as the subsequent alphabet letter.

Original entry on oeis.org

0, 1, 3, 7, 17, 43, 119, 351, 1115, 3735, 13231, 48927, 189079, 757583, 3148063, 13497599, 59704335, 271503647, 1268817471, 6078518911, 29837183007, 149789875903, 768674514815, 4026518397439, 21518708975039, 117199152735615, 650184360936191, 3670861106911743
Offset: 1

Views

Author

Alois P. Heinz, Oct 23 2017

Keywords

Comments

Numbers n such that A291057(n) equals 1.
Numbers n such that the smallest nonzero term in column n of A293815 equals 1.

Examples

			0 is a term because there is only one length minimal language with 0 words: {}.
1 is a term: {a}.
3 is a term: {a, aa, ab}.
7 is a term: {a, aa, ab, aaa, aab, aba, abc}.
17 is a term: {a, aa, ab, aaa, aab, aba, abc, aaaa, aaab, aaba, aabb, aabc, abaa, abab, abac, abca, abcd}.
		

Crossrefs

Programs

  • Maple
    a:= proc(n) option remember; `if`(n<4, n*(n-1)/2,
          2*a(n-1)+(n-3)*a(n-2)-(n-2)*a(n-3))
        end:
    seq(a(n), n=1..30);

Formula

a(n) = a(n-1) + A000085(n-1) for n>1, a(1) = 0.
a(n) = 2*a(n-1)+(n-3)*a(n-2)-(n-2)*a(n-3) for n>= 4, a(n) = n*(n-1)/2 for n<4.
a(n) = A245176(n-1) - 1 for n>0.

A067897 a(n) = A000085(n) - (1 + Sum_{j=1..n-1} A000085(j)).

Original entry on oeis.org

0, 0, 0, 0, 2, 8, 32, 112, 412, 1504, 5760, 22464, 91224, 379424, 1632896, 7201472, 32709136, 152094976, 725810176, 3540883968, 17680145184, 90115509888, 469094763008, 2489169367808, 13465672180160, 74161734785536
Offset: 0

Views

Author

Ian Mooney, May 15 2003

Keywords

Examples

			a(5) = A000085(5) - (1 + Sum_{j=1..4} A000085(j)) = 26 - (1 + 1 + 2 + 4 + 10) = 26 - 18 = 8. - _Jon E. Schoenfield_, Mar 14 2021
		

Crossrefs

Formula

a(n) = A000085(n) - A245176(n-1). - Jon E. Schoenfield, Mar 14 2021

Extensions

Missing initial 0 term added by Jon E. Schoenfield, Mar 16 2021
Showing 1-2 of 2 results.